Answer:
a = 0.5195 m/s²
θ = 9.997º ≈ 10º
Explanation:
We apply Newton's 2nd Law as follows:
∑ Fx = m*ax
∑ Fy = m*ay
Then we have
∑ Fx = F₁x + F₂x = m*ax ⇒ 600*Cos 40º + 600*Cos (-20º) = 2000*ax
⇒ ax = 0.5117 m/s²
∑ Fy = F₁y + F₂y = m*ay ⇒ 600*Sin 40º + 600*Sin (-20º) = 2000*ay
⇒ ay = 0.0902 m/s²
the magnitude of the acceleration of the barge is
a = √(ax² + ay²) = √((0.5117 m/s²)² + (0.0902 m/s²))= 0.5196 m/s²
and the direction is
θ = Arctan (ay / ax) = Arctan (0.0902 / 0.5117) = 9.997º ≈ 10º
Answer:
2.12 J
Explanation:
Initial kinetic energy = final elastic energy + work by friction
KE = EE + W
KE = ½ kx² + W
5 J = ½ (1600 N/m) (0.06 m)² + W
W = 2.12 J
An example of a balanced force would be a book sitting on a shelf untouched.
Isaac Newton’s First Law of Motion states that an object at motion stays in motion, and an object at rest stays at rest until acted on by an unbalanced force. A book sitting still is an example of a balanced force because nothing is acting on it; its potential energy is stored while it’s at rest. For this book to become an unbalanced force, an outside force would have to occur (i.e pushing the book or dropping it) that causes it to not be in a state of stillness.
