Question

How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest to 51 m/s?

Answer 1

Answer:

 t  = 16.5s

Explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity  = 0m/s

Final velocity  = 51m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

        Acceleration  = $\frac{v - u }{t}$  

v is the final velocity

u is the initial velocity

t is the time taken

  So;

       3.1  = $\frac{51 - 0}{t}$  

    3.1t  = 51

       t  = 16.5s