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givi [52]
3 years ago
13

How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest to 51 m/s?

Physics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

 t  = 16.5s

Explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity  = 0m/s

Final velocity  = 51m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

        Acceleration  = \frac{v  - u }{t}  

v is the final velocity

u is the initial velocity

t is the time taken

  So;

       3.1  = \frac{51 - 0}{t}  

    3.1t  = 51

       t  = 16.5s

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Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The
tia_tia [17]

Answer:

Explanation:

capacitance of sphere 2 will be 4.5 times sphere 1

a ) when spheres are in contact they will have same potential finally . So

V_1 / V_2 = 1

b )

Charge will be distributed in the ratio of their capacity

charge on sphere1 = q  x 1 / ( 1 + 4.5 )

= q / 5.5

fraction = 1 / 5.5

c ) charge on sphere 2

= q x 4.5 / 5.5

fraction = 4.5 / 5.5

d ) surface charge density of sphere 1

= q /( 5.5 x A ) where A is surface area

surface charge density of sphere 2

= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area

= q  /( 5.5 x 4.5 A )

q_1/q_2 = 4.5

6 0
3 years ago
A 403.0-kg copper bar is melted in a smelter. The initial temperature of the copper is 320.0 K. How much heat must the smelter p
aleksklad [387]
The answer is 2.49 x 10^5 KJ. This was obtained (1) use the formula for specific heat to achieve Q or heat then (2) get the energy to melt the copper lastly (3) Subtract both work and the total energy required to completely melt the copper bar is achieved.
7 0
4 years ago
Read 2 more answers
A horn on a boat sounds a warning, and the sound penetrates the water. How does the frequency of the sound in the air compare to
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<span>Sound travels faster in water than in air because water has closer particles than in air. This means that the wavelength of sound in water is larger and longer. and its frequency is lower than the sound as heard in the air.</span>
7 0
3 years ago
A student attempted to measure the specific latent heat of vaporisation of water.
tensa zangetsu [6.8K]

Answer:

The latent heat of vaporization of water is 2.4 kJ/g

Explanation:

The given readings are;

The first (mass) balance reading (of the water) in grams, m₁ = 581 g

The second (mass) balance reading (of the water) in grams, m₂ = 526 g

The first joulemeter reading in kilojoules (kJ), Q₁ = 195 kJ

The second joulemeter reading in kilojoules (kJ), Q₂ = 327 kJ

The latent heat of vaporization = The heat required to evaporate a given mass water at constant temperature

Based on the measurements, we have;

The latent heat of vaporization = ΔQ/Δm

∴ The latent heat of vaporization of water = (327 kJ - 195 kJ)/(581 g - 526 g) = 2.4 kJ/g

The latent heat of vaporization of water = 2.4 kJ/g

6 0
3 years ago
3) An electron moves in a circular orbit of radius 0.11 mm, counterclockwise as you look down at it, moving in a plane above and
andrey2020 [161]

Answer:

B = 0.15 T

Explanation:

To find the magnitude of the magnetic field you use the following formula:

B=\frac{mv}{qr}   ( 1 )

m: mass of the electron = 9.1*10^-31 kg

v: velocity of the electron = 3*10^6 m/s

q: charge = 1.6*10^-19

r: radius = 0.11mm = 0.11*10^-3 m

You replace the values of the parameters in the equation (1).

B=\frac{(9.1*10^{-31}kg)(3*10^6\frac{m}{s})}{(1.6*10^{-19}C)(0.11*10^{-3}m)}=0.15T

the magnetic field has a magnitude of 0.15 T

4 0
3 years ago
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