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3 years ago

How has modern safety equipment found in automobiles helped to counteract Newton’s First Law of Motion?

Physics

1 answer:

Charra [1.4K]3 years ago

8 0

Answer:

Well. the law says "an object in motion stays in motion" So seatbelts could be one. they stop us humans from continuing to move when the car stops.

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Which describes freefall

Sati [7]

A motion where gravity is the only force acting upon it

6 0

4 years ago

A cylinder which is in a horizontal position contains an unknown noble gas at 4.63 × 104 Pa and is sealed with a massless piston

AleksandrR [38]

Answer:

The change in internal energy of the system is -17746.78 J

Explanation:

Given that,

Pressure $P=4.63\times10^{4}\ Pa$

Remove heat $\Delta U= -1.95\times10^{4}\ J$

Radius = 0.272 m

Distance d = 0.163 m

We need to calculate the internal energy

Using thermodynamics first equation

$dU=Q-W$ ...(I)

Where, dU = internal energy

Q = heat

W = work done

Put the value of W in equation (I)

$dU=Q-PdV$

Where, W = PdV

Put the value in the equation

$dU=-1.95\times10^{4}-(4.63\times10^{4}\times3.14\times(0.272)^2\times(-0.163))$

$dU=-17746.78\ J$

Hence, The change in internal energy of the system is -17746.78 J

3 0

4 years ago

The graph represents velocity over time...

Nady [450]

Answer:

where is the graph I can't see it how can I solve the problem if I don't see the graph can you show the graph please

8 0

3 years ago

A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?

Montano1993 [528]

As we know,

$electric \: \: current = \dfrac{charge}{time}$

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

$0.2 = \dfrac{q}{300}$

$q = 300 \times 0.2$

$q = 60$

hence, the charge = 60 coulombs (C)

4 0

3 years ago

The maximum force that a grocery bag can withstand without ripping is 250 n. Suppose that the bag is filled with 20 kg of grocer

zhannawk [14.2K]

Answer:

Groceries stay in the bag.

Explanation:

Given:

Maximum force = 250 N

Bag filled with = 20 kg

Lifted acceleration = $5.0\ m/s^2$

Solution:

We need to calculate the exerted force on the grocery bag by using Newton's second law.

$F = ma$

Where:

F = Exerted force on the object.

m = Mass of the object in kg

a = Acceleration of the object in $m/s^2$

Now, we substitute m = 20 kg and a = $5.0\ m/s^2$ in Newton's second law,

$F = 20\times 5.0$

$F = 100\ m/s^2$

Since, the exerted force on the bag is less than 250 N, the groceries will stay in the bag.

3 0

3 years ago