Answer: The period of the subsequent simple harmonic motion is 1.004 sec.
Explanation:
The given data is as follows.
Mass of disk (m) = 2.2 kg, radius of the disk (r) = 61.2 cm,
Formula to calculate the moment of inertia around the center of mass is as follows.
=
= 0.412 
Also,
Distance between center of mass and axis of rotation (d) = r = 0.612 m
Moment of inertia about the axis of rotation (I)
I = 
I = 
= 0.339 
Now, we will calculate the time period as follows.
T = 
T = 
T = 1.435 sec
T = 
= 1.004 sec
Thus, we can conclude that the period of the subsequent simple harmonic motion is 1.004 sec.
Answer:
Efficiency = StartFraction T Subscript h Baseline minus T Subscript C Baseline over T Subscript h Baseline EndFraction times 100. Efficiency equals T Subscript c Baseline minus T Subscript h Baseline over T Subscript h Baseline all times 100.
Answer:
7.344 s
Explanation:
A = 0.15 x 0.3 m^2 = 0.045 m^2
N = 240
e = - 2.5 v
B1 = 0.1 T
B2 = 1.8 T
ΔB = B2 - B1 = 1.8 - 0.1 = 1.7 T
Δt = ?
e = - dФ/dt
e = - N x A x ΔB/Δt
- 2.5 = - 240 x 0.045 x 1.7 / Δt
2.5 = 18.36 / Δt
Δt = 7.344 s
Thermal energy is converted to radiative energy via molecular collisions and released as photons.