What is the next number? 3 4 6 9 13 18 24

Y = 4x - 7 What is the y-intercept?

RideAnS [48]

Answer:

(0,-7)

Step-by-step explanation:

6 0

2 years ago

What is 2x+3+8x=3x+9x+7

Reika [66]

Answer:

x=-2

Step-by-step explanation:

Hey there!

In order to solve this equation, you need to combine like terms

The equation after combining the x terms and the contants will look like this

10x+3=12x+7

Now you have to take 10x away from both sides

3=2x+7

Now bring all the constants to the left side

3-7=2x

Simplify

-4=2x

divide 2 on both sides to get x by itself

x=-2

So, the answer is x=-2

3 0

2 years ago

A function is a rule that assigns each value of the independent variable to exactly one value of the dependent variable. True or

vesna_86 [32]

The answer is true
Let's imagine that we have the following function function:
 $y = x ^ 2 
$
We have to:
Independent variable: x
Dependent variable: y
For x = -1:
 $y = (- 1) ^ 2 = 1 
$
 For x = 1:
 $y = (1) ^ 2 = 1 
$
 We observe that the independent variable can only obtain one result.
Answer:
True

3 0

2 years ago

Read 2 more answers

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

You and your friend each deposit $50 in separate savings accounts. Your account earns 2% simple annual interest. Your friend’s a

d1i1m1o1n [39]

Answer:

I am will take 20 years to get 20$

My friend will take 10 years to get 20$

Step-by-step explanation:

$Let \: the \: no. \: of \: years : x \\ \\ for \: me \\ x \times (50 \times 2\%) = 20 \\ x \times 1 = 20 \\ x = 20 years\\ for \: my \: friend \\ x \times (50 \times 0.04) = 20 \\ 2x = 20 \\ x = 10 \: years$

I hope this is be good for you and I want this money

7 0

2 years ago