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tekilochka [14]
4 years ago
8

What is the next number? 3 4 6 9 13 18 24

Mathematics
2 answers:
Crazy boy [7]4 years ago
5 0
It is 31.................

attashe74 [19]4 years ago
5 0
The answer would be 31 hope this helps
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I'm pretty sure it's Identity I hope it helps :)
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3 years ago
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A building 30 feet tall casts a shadow 20 feet long. A person 6 feet tall is walking directly away from the building toward the
DIA [1.3K]

Answer:

  16 feet

Step-by-step explanation:

The shadow is 20/30 = 2/3 the length of the object, so the 6-foot person's shadow will be 4 ft long. It will begin to emerge when the person is 4 feet from the tip of the building's shadow. That distance is ...

  20 ft - 4 ft = 16 ft

from the building.

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4 years ago
Tanyas baked goods took in 175$ To help raise money for the chorus club .Tanya need to spend 32$ for baking supplies write and e
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Step-by-step explanation:

6 I think that is the answer I hop you get it right

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3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Convert 6400000 milligrams to kilograms
vodomira [7]

Answer:

Your answer is 6.4 kilograms :D

Step-by-step explanation:

6 0
3 years ago
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