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Vedmedyk [2.9K]
3 years ago
6

How much water do been plants need to grow?

Chemistry
1 answer:
Kruka [31]3 years ago
6 0
They need about one inch of water each week
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A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.
Alenkinab [10]

Answer:

\Delta V = 234.736\,mL

Explanation:

The quantity of moles of ethanol in the solution is:

n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)

n_{C_{2}H_{5}OH} = 4.985\,mol

The mass and volume of ethanol in the solution are, respectively:

m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)

m_{C_{2}H_{5}OH} = 229.658\,g

V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }

V_{C_{2}H_{5}OH} = 290.964\,mL

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)

\Delta V = 234.736\,mL

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3 years ago
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ruslelena [56]
There is one atom of sulfur :)
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3 years ago
Under which of the folowing conditions of temperature and pressure wil H2 gas be expected to behave most like an ideal gas ?
Brilliant_brown [7]

Answer:

C ( 500K and 0.1atm)

Explanation:

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2 years ago
What is c4???????<br><br> will give brainliest if right
Lena [83]

C-4 or Composition C-4 is a common variety of the plastic explosive family known as Composition C, which uses RDX as its explosive agent. C-4 is composed of explosives, plastic binder, plasticizer to make it malleable, and usually a marker or odorizing taggant chemical.

Or

The explosive material in C-4 is cyclotrimethylene-trinitramine (C3H6N6O6), commonly called RDX (which stands for "royal demolition explosive" or "research development explosive").

5 0
4 years ago
Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the pr
enot [183]

Answer:

ΔG = -8.812 kJ/mol

Explanation:

To obtain the free energy of a reaction you can use the expression:

ΔG = ΔG° + RT ln Q

<em>Where: </em>

<em>ΔG° is Standard Gibbs Free energy: -16.7kJ/mol = -16700J/mol</em>

<em>R is gas constant: 8.314472 J/molK</em>

<em>T is absolute temperature (37°C + 273.15 = 310.15K)</em>

<em>And Q is reaction quotient: 21.3</em>

<em />

Replacing in the formula:

ΔG = ΔG° + RT ln Q

ΔG = -16700J/mol + 8.314472J/molK*310.15K ln 21.3

ΔG = -8812.4J/mol

<h3>ΔG = -8.812 kJ/mol</h3>

<em />

7 0
4 years ago
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