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Arisa [49]
3 years ago
10

A uniform charge density of 500nC/m^3 is distributed throughout a spherical volume (radius 16cm). Consider a cubical (4cm along

each edge) surface completely inside the sphere. Determine the electric flux through the surface of the cube.
Physics
1 answer:
liraira [26]3 years ago
8 0

Answer:

3.61581\ Nm^2/C

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

V = Volume of cube = 0.04^3

\rho = Charge density = 500\ nC/m^3

Electric flux is given by

\phi=\dfrac{Q}{\epsilon_0}\\\Rightarrow \phi=\dfrac{\rho V}{\epsilon_0}\\\Rightarrow \phi=\dfrac{500\times 10^{-9}\times 0.04^3}{8.85\times 10^{-12}}\\\Rightarrow \phi=3.61581\ Nm^2/C

The electric flux through the surface of the cube is 3.61581\ Nm^2/C

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1000 millimeters

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equilibrium

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A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

v = 25m/s

u = 15m/s

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∆P = 1500×10

∆P = 15,000kgm/s

Since the car first travels due East i.e +x direction

x = 25m/s

Travelling due south is negative y direction

y = -15m/s

Direction of the car change

θ = tan^-1(y/x)

θ = tan^-1(-15/25)

θ = tan^-1(-0.6)

θ = -30.96°

Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

5 0
4 years ago
The motion of a free falling body is an example of........................motion
nirvana33 [79]
A body that is falling is an example of gravity at work.
7 0
3 years ago
3. An automobile accelerates 1.77 m/sover 6.00 s to reach the freeway speed at
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The initial speed of the automobile is 49.84km/hr

<u>Explanation:</u>

Given:

Acceleration, a = 1.77 m/s²

Time, t = 6s

Final speed, v = 88 km/h

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Initial speed, u = ?

We know,

v = u + at

On substituting the value in the formula we get:

24.464 = u + (1.77 X 6)

24.464 = u + 10.62

u = 24.464 - 10.62 m/s

u = 13.844 m/s

Converting u = 13.844 m/s to km/hr

1 m/s = 3.6 km/hr

13.844 m/s = 13.844 X 3.6 km/hr

u = 49.84 km/hr

Therefore, the initial speed of the automobile is 49.84km/hr

4 0
4 years ago
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