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Alinara [238K]
3 years ago
9

If a toy car covers a distance of 42m in 7sec, what is it’s speed

Engineering
2 answers:
S_A_V [24]3 years ago
6 0

Answer:

6m/s

Explanation:

This is a basic division problem. To solve divide 42 by 7 to find its speed (meters/second).

42/7 is 6.

PSYCHO15rus [73]3 years ago
3 0

Answer: The answer would be 6m/s

Divide how much distance it covers (42m) in 7 seconds.

What we have: 42/7

42 divided by 7 is 6

If you're still not sure, do 6 times 7 to check again

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avanturin [10]

Answer:

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Explanation:

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6 0
2 years ago
What effect does air have on the acceleration of aircraft during flight?
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5 0
2 years ago
2. A well of 0.1 m radius is installed in the aquifer of the preceding exercise and is pumped at a rate averaging 80 liter/min.
hodyreva [135]

Question:

The question is not complete. See the complete question and the answer below.

A well that pumps at a constant rate of 0.5m3/s fully penetrates a confined aquifer of 34 m thickness. After a long period of pumping, near steady state conditions, the measured drawdowns at two observation wells 50m and 100m from the pumping well are 0.9 and 0.4 m respectively. (a) Calculate the hydraulic conductivity and transmissivity of the aquifer (b) estimate the radius of influence of the pumping well, and (c) calculate the expected drawdown in the pumping well if the radius of the well is 0.4m.

Answer:

T = 0.11029m²/sec

Radius of influence = 93.304m

expected drawdown = 3.9336m

Explanation:

See the attached file for the explanation.

8 0
3 years ago
A waste stabilization pond is used to treat a dilute municipal wastewater before the liquid is discharged into a river. The infl
german

Answer:

BOD concentration at the outflow = 17.83 mg/L

Explanation:

given data

flow rate of Q = 4,000 m³/day

BOD1 concentration of Cin = 25 mg/L

volume of the pond = 20,000 m³

first-order rate constant equal = 0.25/day

to find out

What is the BOD concentration at the outflow of the pond

solution

first we find the detention time that is

detention time t = \frac{volume}{flow rate}

detention time t = \frac{20000}{4000}

detention time = 5 days

so

BOD concentration at the outflow of pond is express as

BOD concentration at the outflow = Cin ( 1 - e^{-kt} )

here k is first-order rate constant and t is detention time and Cin is BOD1 concentration

so

BOD concentration at the outflow = 25 ( 1 - e^{-0.25(5)} )

BOD concentration at the outflow = 17.83 mg/L

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