Answer:
Ig =7.2 +j9.599
Explanation: Check the attachment
Answer:
P = 80.922 KW
Explanation:
Given data;
Length of load arm is 900 mm = 0.9 m
Spring balanced read 16 N
Applied weight is 500 N
Rotational speed is 1774 rpm
we know that power is given as
![P = T\times \omega](https://tex.z-dn.net/?f=%20P%20%3D%20T%5Ctimes%20%5Comega)
T Torque = (w -s) L = (500 - 16)0.9 = 435.6 Nm
angular speed
Therefore Power is
![P =\frac{435.6 \time 2 \pi \times 1774}{60} = 80922.65 watt](https://tex.z-dn.net/?f=P%20%3D%5Cfrac%7B435.6%20%5Ctime%202%20%5Cpi%20%5Ctimes%201774%7D%7B60%7D%20%3D%2080922.65%20%20watt)
P = 80.922 KW
The displacement ∆S of the particle during the interval from t = 2sec to 4sec is; 210 sec
<h3>How to find the displacement?</h3>
We are given the velocity equation as;
s' = 40 - 3t²
Thus, the speed equation will be gotten by integration of the velocity equation to get;
s = ∫40 - 3t²
s = 40t - ¹/₂t³
Thus, the displacement between times of t = 2 sec and t = 4 sec is;
∆S = [40(4) - ¹/₂(4)³] - [40(2) - ¹/₂(2)³]
∆S = 210 m
Read more about Displacement at; brainly.com/question/4931057
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