The 1kg ball would exert the smallest force.
As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.
When the mass is lighter (1kg):
Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N
Compared to when the mass is heavier (10kg)
Force = mass x gravity
Force = 10 x 9.8
Force = 98N
Where this proves that the lighter the mass, the smaller the force exerted.
Atoms are made up of three particles: protons, neutrons and electrons. Protons and neutrons are heavier than electrons and reside in the center of the atom, which is called the nucleus.Jun 5, 2013-livescience.com
The amount of work the two tugboats completed on the supertanker W = 3.12 × 10^9 joules .
Work is a physics term used to describe the energy transfer that takes place when an object is moved over a distance by an external force, at least some . The component of the force acting along the path multiplied by the length of the path can be used to calculate work if the force is constant. Mathematically, this idea is expressed as W = fd, where W is the work and f is the force multiplied by d, the distance. Work is completed when the force is applied at an angle of with respect to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as other methods. However, the work is thought to be negative if the applied force is in opposition to the item's motion, indicating that energy is being pulled away from the object
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Grav Force = GMm/r squared. M is earth's mass. m is the probe. r is distance to centre of earth.Given that 600 = GMm/(10,000^2).GMm = 600x(10,000^2) for 10, 000 milesGMm = ? x (20,000^2) for 20, 000 milestherefore600x(10,000^2)=? x (20,000^2)therefore [600x(10,000^2)]/(20,000^2)=? [600x(1x1)]/(2x2)=? [600/4]=? ?=150lb.Same procedure for b and c.Please ask if you want further help.
Answer:
Frictional force, f = 20 N
Explanation:
It is given that,
Weight of the crate, W = 40 N
Horizontal force acting on the crate, F = 12 N
The coefficient of static friction, 
The coefficient of kinetic friction, 
Let f is the frictional force acting on the crate. Friction is an opposing force. It is equal to the product of coefficient friction and the normal force. It is given by :


f = 20 N
So, the frictional force on the crate is 20 N. Hence, this is the required solution.