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olchik [2.2K]
3 years ago
9

Is evaporation/condensation a physical or chemical change? Explain

Chemistry
1 answer:
jenyasd209 [6]3 years ago
4 0
Physical change because it still has the same chemical formula
You might be interested in
A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.
Archy [21]

Answer:

a) 0.003512 moles

b) Moles C= 0.04214 moles carbon

Moles H = 0.07726 moles hydrogen

Moles O = 0.03863 moles of oxygen

c) C atoms = 2.54 *10^22 carbon atoms

H atoms = 4.65 *10^22 hydrogen atoms

O atoms = 2.33 *10^22 oxygen atom

Explanation:

Step 1: Data given

Mass of sucrose = 1.202 grams

Molar mass of sucrose = 342.3 g/mol

Step 2: Calculate moles of sucrose

Moles sucrose = Mass sucrose / molar mass sucrose

Moles sucrose = 1.202 grams / 342.3 g/mol

Moles sucrose = 0.003512 moles

Step 3: Calculate moles of each element

For 1 mol of C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen

Moles C: 12*0.003512 = 0.04214 moles carbon

Moles H: 22* 0.003512 = 0.07726 moles hydrogen

Moles O: 11* 0.003512 = 0.03863 moles of oxygen

Step 4: Calculate the number of atoms

C atoms = 6.022 *10^23 / mol * 0.04214 moles = 2.54 *10^22 atoms carbon

H atoms = 6.022 * 10^23 / mol * 0.07726 moles = 4.65 *10^22 atoms H

O atoms = 6.022 * 10^23 / mol * 0.03863 moles = 2.33 *10^22 atoms O

0.003512 moles of sucrose containse 6.022 *10^23 * 0.003512 = 2.11 * 10^21 sucrose molecules

7 0
3 years ago
For each situation below, state whether water will move into the cell, move out of the cell, or stay the same.
Firdavs [7]
Water moves from an area of higher water potential (aka. "more water" in simple language) to an area of lower water potential (aka. "less water" in simple language).

For A, cells in carrots have water stored in their cytoplasm, where many soluble substances may be found (e.g. sodium ions). On the other hand, pure water has no other soluble substances other than the water molecules (I.e. H2O). Pure water will thus have a higher water potential as compared to the water in carrot cells, and so, water will move from pure water into the carrot cells via osmosis down a concentration gradient.

B. Corn syrup is water that has high concentrations of sugars, thus it is very likely to have a lower water potential than the cells of carrots. Water will move from within the cells of carrots and out to the corn syrup, down a concentration gradient.

C. The water in carrot cells will stay the same, since carrot cells have the same water potential as the surrounding solution which has the same water potential as cytoplasm.

Hope this helps! :)
8 0
3 years ago
24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!
erastovalidia [21]
I'd say b, but i'm not 100 percent sure.<span />
6 0
3 years ago
Read 2 more answers
what is the balanced equation for the reaction of solid magnesium metal with oxygen gas to produce solid magnesium oxide
GaryK [48]

Answer:

2Mg + O₂ ⟶ 2MgO

Explanation:

Step 1. Start with the most complicated-looking formula (O₂?).

Put a 1 in front of it.

Mg + 1O₂ ⟶ MgO

Step 2. Balance O.

We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

Mg + 1O₂ ⟶ 2MgO

Step 3. Balance Mg.

We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.

2Mg + 1O₂ ⟶ 2MgO

Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u>  <u>On the left</u>  <u>On the righ</u>t

  Mg             2                  2

  O                2                  2

All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

4 0
3 years ago
An object has a mass of 5.52 g and a volume of 12 mL. What is the density of the object?
Rudik [331]

Answer:

<h2>Density = 0.46 g/mL</h2>

Explanation:

Density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question

mass = 5.52 g

volume = 12 mL

Substitute the values into the above formula and solve for the Density

That's

<h3>Density =  \frac{5.52}{12}</h3>

We have the final answer as

<h3>Density = 0.46 g/mL</h3>

Hope this helps you

4 0
3 years ago
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