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klasskru [66]
3 years ago
10

Describe electric discharge

Physics
2 answers:
Angelina_Jolie [31]3 years ago
8 0
An electric discharge is the release and transmission of electricity in an applied electric field through a medium such as a gas. Several types of electric discharges occur naturally on Earth (American Geophysical Union, 1986):
ASHA 777 [7]3 years ago
6 0
A Electric Discharge is the release and transmission of electricity.

Hope I Helped! ( Smiles )
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The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
vivado [14]

The force the escaping gas exerts of the rocket is 10.42 N.

<h3>Force escaping gas exerts</h3>

The force the escaping gas exerts of the rocket is calculated as follows;

F = m(v - u)/t

where;

  • m is mass of the rocket
  • v is the final velocity of the rocket
  • u is the initial velocity of the rocket
  • t is time of motion

F = (0.25)(40 - 15)/0.6

F = 10.42 N

Thus, the force the escaping gas exerts of the rocket is 10.42 N.

Learn more about force here: brainly.com/question/12970081

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7 0
2 years ago
En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua​
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Explanation:

En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua

5 0
2 years ago
What is the weight of a rock with a mass of 3.6 kilograms
Marysya12 [62]
3.85 pounds is the answer
4 0
3 years ago
What is 8200 N/m2 expressed in kilopascals?
natima [27]
The S.I. unit for the measure of the pressure is the Pascal (Pa). 1 Pascal corresponds to
1 Pa = 1 N/m^2

We can convert the number given by the problem into Pascal:
8200 N/m^2 = 8200 Pa

And since 1 Pa = 10^{-3}kPa, we have
8200 Pa = 8200 \cdot 10^{-3}kPa =8.2 kPa
5 0
3 years ago
If a pickup is placed 16.25 cm from one of the fixed ends of a 65.00-cm-long string, which of the harmonics from n=1 to n=12 wil
Lina20 [59]

Answer:

The answer to this question can be defined as follows:

Explanation:

Therefore the 4th harmonicas its node is right and over the pickup so, can not be captured from 16.25, which is 1:4 out of 65. Normally, it's only conceptual for the certain harmonic, this will be low, would still be heard by the catcher.

Instead, every harmonic node has maximum fractions along its string; the very first node is the complete string length and the second node is half a mile to the third node, which is one-third up and so on.

4 0
3 years ago
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