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3 years ago

Describe electric discharge

2 answers:

8 0

An electric discharge is the release and transmission of electricity in an applied electric field through a medium such as a gas. Several types of electric discharges occur naturally on Earth (American Geophysical Union, 1986):

ASHA 777 [7]3 years ago

6 0

A Electric Discharge is the release and transmission of electricity.

Hope I Helped! ( Smiles )

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Which of the following objects has the greatest density

maks197457 [2]

The density is determined on the steepness of the slope. The greater the density is bases upon the steepest slope. To conclude, I'd say Line A has the steepest slope therefore has the greatest density.

6 0

3 years ago

Read 2 more answers

Which of the following is NOT true about the structure of the nucleus? a. The nucleus is filled with cytoplasm b. The nucleus ha

Cerrena [4.2K]

Answer:

A. The nucleaus is filled with cytoplasm OR d. The nucleus is by a double layer membrane.

Explanation:

b. and c. are true and I'm certain they are true

a. I know the inside of a cell has cytoplasm but I'm not sure if the inside of a nucleus is filled with cytoplasm. And d. I'm not so sure, so it's either a or d. Hope this helps!

3 0

3 years ago

As distance increases, force decrease and vise versa, as distance decreases then, force increases. This is a ________________ re

Sonbull [250]

It is indirectly proportional or inverse so it would be C

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2 years ago

What is an unbalanced force. in your own words but be more detailed.

pogonyaev

Answer:

An unbalanced force is a force that causes an object's state of motion to change. In other words, unbalanced forces are the things that make objects speed up or slow down.

Explanation:

(self-explanatory)

7 0

2 years ago

A small car with mass m and speed 2v and a large car with mass 2m and speed v both travel the same circular section of an unbank

Alenkasestr [34]

Answer:

(D) F/2

Explanation:

Since the circular section is unbanked, the centripedal acceleration acting on each of the cars is

$a_s = \frac{v_s^2}{r} = \frac{(2v)^2}{r} = \frac{4v^2}{r}$

$a_l = \frac{v_l^2}{r} = \frac{v^2}{r}$

Therefore the centripetal force on each car

$F_s = m_sa_s = \frac{4mv^2}{r}$

$F_l = m_la_l = \frac{2mv^2}{r}$

Since $F_s = 2F_l$ this means the friction force required to keep the large car on the road is only half of the friction force required to keep the small car on road

So (D) F/2 is the correct answer

5 0

3 years ago