Answer is: concentration of hydrogen iodide is 6 M.
Balanced chemical reaction: H₂(g) + I₂(g) ⇄ 2HI(g).
[H₂] = 0.04 M; equilibrium concentration of hydrogen.
[I₂] = 0.009 M; equilibrium concentration of iodine.
Keq = 1·10⁵.
Keq = [HI]² / [H₂]·[I₂].
[HI]² = [H₂]·[I₂]·Keq.
[HI]² = 0.04 M · 0.009 M · 1·10⁵.
[HI]² = 36 M².
[HI] = √36 M².
[HI] = 6 M.
Answer:
Carbon-14 or C-14
Explanation:
Since the isotope is a carbon isotope, it means the the atomic number of the isotope is 6.
The atomic number of an element is the proton number.
Therefore, the isotope has a proton number of 6
Now we need to obtain the mass number of isotope in order to write the symbol of the isotope. This is illustrated below:
Mass number = Proton +Neutron
Proton = 6
Neutron = 8
Mass number = 6 + 8
Mass number = 14
Therefore, the symbol of the isotope is carbon-14 or C-14
Answer:
B. It tells whether products or reactants are favored at equilibrium.
S because As is not a non-metal
