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nalin [4]
3 years ago
8

Sulfuric acid will react with which of the following to form sulfur dioxide gas Select one: a. Sodium sulfite b. Thioacetamide c

. Sodium sulfate d. Oxygen Clear my choice
Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

Sodium sulfite (Na2SO3)

Explanation:

Sulfuric acid is able to displace volatile acids from their corresponding salts and the acids displaced are unstable and they break down to give volatile products

For example, in to reaction of sulfuric acid and sodium sulfite; two processes occur

1. Sulfuric acid forms sodium sulfate and sulfurous acid

Na2SO3(s) + H2SO4(aq) -------> Na2SO4(aq) + H2SO3

2. The H2SO3 is unstable thereby decompose spontaneously to water and sulfur dioxide gas.

H2SO3 -----------> H2O(l) + SO2(g)

Final reaction gives;

Na2SO3(s) + H2SO4 (aq) ---------> Na2SO4(aq) + H2O(l) + SO2(g)

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In response to boyle’s law, the pressure of a gas increases as the volume decreases because
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because the gas particles are forced closer together.
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3 years ago
Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
2 years ago
Examine the statement.
vlada-n [284]

Answer:disagree. Temperature increases, water expands.

Explanation:

5 0
2 years ago
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Calculate the oxidation state of the underlined elements of K2 Cr2 O7
Semenov [28]

Answer:

+4

Explanation:

In PbO2, oxygen exhibits an oxidation number of -2 (since it's not a peroxide or superoxide):

Let the oxidation number of Pb be x. Then, for the compound to be neutral, the oxidation numbers of all atoms should add up to zero.

⇒ x + (−2) + (−2) = 0

x = +4

So the oxidation no. of Pb is +4.

I hope this helps.

3 0
2 years ago
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First convert grams to moles using molar mass of butane that is 58.1 g

3.50g C4H10 x (1 mol C4H10)/(58.1g C4H10) = 0.06024 mol C4H10 <span>

<span>Now convert moles to molecules by using Avogadro’s number

0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 mol C4H10) = 3.627x10^22 molecules C4H10 

And there are 4 carbon atoms in 1 molecule of butane, so use the following ratio: 

3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 molecule C4H10) 
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7 0
2 years ago
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