All categories

3 years ago

WRITE INCOMPLETE COMBUSTION OF ETHANE

Chemistry

1 answer:

Rainbow [258]3 years ago

8 0

The equation for the incomplete combustion of ethane is as follows:
2C2H6(g)+5O2(g)—>4CO(g)+6 H2O(l)

You might be interested in

Which of the following is the correct name for the compound S3Cl2? Sulfur chloride Sulfur (III) chloride Sulfur (II) chloride Tr

Rus_ich [418]

Sulfur is not a transition metal so it does not need a Roman numeral the correct answer is Trisulfur Dichloride

8 0

3 years ago

Read 2 more answers

64. Which of the followings can dissociate in water?

Arisa [49]

Answer:

<h2>Hi there !</h2>

Explanation:

<h2>Reason :-</h2>

<h2>Salts are strong electrolytes, so they undergo complete dissociation.</h2><h3>Hope it helps u.....</h3><h3>Stay safe, stay healthy and blessed</h3><h3>Have a good day</h3><h3>Thank you ~</h3>

8 0

1 year ago

Read 2 more answers

onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency

mestny [16]

Answer : The excess reactant is, $H_2O$

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of $CaCN_2$ = 105.0 g

Mass of $H_2O$ = 78.0 g

Molar mass of $CaCN_2$ = 80.11 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $CaCO_3$ = 100.09 g/mole

First we have to calculate the moles of $CaCN_2$ and $H_2O$ .

$\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles$

$\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $CaCN_2$ react with 3 mole of $H_2O$

So, 1.31 moles of $CaCN_2$ react with $1.31\times 3=3.93$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $CaCN_2$ is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

$\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)$

$\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g$

Thus, the leftover amount of excess reagent is, 7.2 grams.

8 0

3 years ago

This part insulates the reaction chamber from the transfer of heat to or from the surrounding environment. this part contains a

Masja [62]

The amount of heat transferred in and out of the system is measured by calorimetry. The thermometer in the calorimeter is used to measure the temperature.

<h3>What are the parts of the calorimetry device?</h3>

The thermometer (A) is a device used to measure the final and the initial temperature of the water or any other liquid in a system. A metal vessel is a place where the reaction mixture is present.

In-vessel (B), water, and metal are placed before the beginning of the experiment. The styrofoam cup or the outer metal vessel (C) insulates the instrument, from regulating the heat transformation.

Therefore, part A measures the temperature of the reaction mixture.

Learn more about insulated containers here:

brainly.com/question/866735

3 0

1 year ago

What is the name of the element with the atomic number 79

natima [27]

Look it up, it’s not that hard.

6 0

2 years ago