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lara [203]
3 years ago
7

WRITE INCOMPLETE COMBUSTION OF ETHANE

Chemistry
1 answer:
Rainbow [258]3 years ago
8 0
The equation for the incomplete combustion of ethane is as follows:
2C2H6(g)+5O2(g)—>4CO(g)+6 H2O(l)
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PLEASE!!! I NEED HELP ASAP!!
Lana71 [14]
W=m₁/m₀=2^(-t/T)

t=4.6·10⁹ years
T=5·10¹⁰ years

w=2^(-4.6·10⁹/5·10¹⁰)

w=0.9382
w=93.82%

7 0
3 years ago
Read 2 more answers
If 17.8 grams of KOH dissolve in enough water to make a 198-gram solution, what is the concentration in percent by mass?
sleet_krkn [62]
Solute of solution = 17.8 g

Solvn = 198 g

% = 17.8 / 198

w% = 0.089 x 100 = 8.9%  by mass

hope this helps!
7 0
3 years ago
What is the mole ratio of NH3 to N2?
Ksenya-84 [330]
To answer this question a balanced chemical equation is necessary. The correct equation is: N2 + 3H2 = 2NH3
From this equation, one mole of nitrogen react with 3 moles of hydrogen to give 2 moles of ammonia.
Therefore, the mole ratio of NH3 to N2 is 2:1
8 0
3 years ago
You have a solution that is 0.02M formate (HCOO-) and 0.03M formic acid (HCOOH), which has a Ka of 1.8x10-4. What is the pH of t
lisov135 [29]

Answer:

3.6

Explanation:

Step 1: Given data

  • Concentration of formic acid: 0.03 M
  • Concentration of formate ion: 0.02 M
  • Acid dissociation constant (Ka): 1.8 × 10⁻⁴

Step 2: Calculate the pH

We have a buffer system formed by a weak acid (HCOOH) and its conjugate base (HCOO⁻). We can calculate the pH using the <em>Henderson-Hasselbach equation</em>.

pH = pKa +log\frac{[base]}{[acid]} = -log 1.8 \times 10^{-4} + log \frac{0.02}{0.03} = 3.6

6 0
3 years ago
Which statement about silver Ag metal is least reliable
Anna007 [38]
<span>The choices for this question can be found elsewhere and as follows:

Silver is a transition metal with electrons in the d shell.
Silver atoms have 47 protons in their nuclei.
Silver atoms commonly form ions with a +1 charge.

I think the correct answer is the last option. The least reliable information would be that s</span>ilver atoms commonly form ions with a +1 charge.
3 0
3 years ago
Read 2 more answers
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