1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marishachu [46]
3 years ago
7

You have 4.5 x 10^24 particles of C3H8. How many grams are present?

Chemistry
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

33 g.

Explanation:

Hello there!

In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:

1mol=44.11g=6.022x10^{23}molecules

In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:

4.5x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} *\frac{44.11g}{1mol}\\\\33g

Best regards!

You might be interested in
Explain how scientists use geologic time to determine the age of land forms.
valentina_108 [34]
I am sorry i wish i could help you but i dont know the answer either.
5 0
3 years ago
In the summer of 2016, the city of Columbus Dublin Road Water Treatment plan exceeded the regulatory level of nitrate, which is
Verizon [17]

Answer:

a) 10 mg NO_3^-/L

b) 1.61*10^{-4}mol NO_3^-/L

c) 2.26 mg N/L

Carbon: C=26.64 \frac{mg C}{L}

Explanation:

<u>Nitrate</u>

First of all, is important to know that:

1 ppm=1 mg/L

a) 10 ppm of nitrate (NO_3^-) is equal to 10 mg NO_3^-/L

b) The molecular weight of nitrate is 62 g NO_3^-/mol

10 mg NO_3^-/L=0.01 g NO_3^-/L

\frac{0.01 g NO_3^-/L}{62 g NO_3^-/mol}=1.61*10^{-4} mol NO_3^-/L

c) Nitrate has 14 mg of N per 62 mg of NO3

10 mg NO_3^-/L*\frac{14 mg N}{62 mg NO_3^-}=2.26 mg N/L

<u>Carbon</u>

Carbonate has 12 mg of C per 60 mg of CO_3^{-2}

Bicarbonate has 12 mg of C per 61 mg of HCO_3^{-}

C=24 \frac{mg CO_3^{-2}}{L}*\frac{12 mg C}{60 mg CO_3^{-2}}+111 \frac{mg HCO_3^{-}}{L}*\frac{12 mg C}{61 mg HCO_3^{-}}

C=26.64 \frac{mg C}{L}

8 0
3 years ago
How is iron extracted? Describe in brief​
Feliz [49]

Answer:Iron is extracted from iron ore in a huge container called a blast furnace. Iron ores such as haematite contain iron(III) oxide, Fe 2O 3. The oxygen must be removed from the iron(III) oxide in order to leave the iron behind. Reactions in which oxygen is removed are called reduction reactions.

3 0
3 years ago
Read 2 more answers
In Lewis dot diagrams, valence electrons are represented by dots around the atomic symbol. How many electrons should around an a
Margaret [11]
There should be 3 valence electrons surrounding the aluminum ion
8 0
3 years ago
Read 2 more answers
What do food webs begin with as the first source of energy A plants B consumers C the sun D decomposers
atroni [7]

Answer:

C:sun

Explanation:

3 0
3 years ago
Other questions:
  • A gas has a pressure of 50.0 mmHG at a temperature of 540 K. What will be the temperature if the pressure goes down to 3 mmHg?
    13·2 answers
  • A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
    9·1 answer
  • The parent element 247 95 am decays by beta decay which daughter element will formn
    14·1 answer
  • The pressure exerted by a gas on its container is inversely related to its Kelvin temperature
    13·1 answer
  • Wafting the air above a chemical is one way to it directly
    6·1 answer
  • What is the SI unit of time?<br><br> Asecond<br> B. minute<br> C. hour<br> D. day
    10·1 answer
  • Convert the following Grams: 0.200 moles of H2S
    11·1 answer
  • What is the main function of the part labeled Yin the model?
    12·1 answer
  • In a water molecule, the shared electrons spend more time around
    11·1 answer
  • On a summer day early in the moming, a balloon is filled with helium when the temperature
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!