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dlinn [17]
3 years ago
15

An inkjet printer's speed is measured in ____. select one:

Physics
1 answer:
Vladimir [108]3 years ago
5 0
<span>Back in the day, one measured a printer's speed in CPM, which stands for characters per minute. Most of the modern printers that exist today, including the inkjet printer measure their speed in PPM, which is also known as pages per minute.</span>
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How is heat involved in changing the phase of a substance from solid to liquid to gas?
natali 33 [55]

Answer:do it correct and do your best please yourself do what is right let every body know this is ak200342 talking to you.

Explanation:keep your head up.

3 0
3 years ago
A car speeds up from 3 m/s to 10 m/s in 8 s. How far does the car travel while doing this? 2. A
yarga [219]

Initial velocity=u=3m/s

Final velocity=v=10m/s

Time=t=8s

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}

\\ \sf\longmapsto Acceleration=\dfrac{7}{8}

\\ \sf\longmapsto Acceleration=0.8m/s^2

  • Distance =s

Using second equation of motion

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2

\\ \sf\longmapsto s=24+0.4(64)

\\ \sf\longmapsto s=24+25.6

\\ \sf\longmapsto s=49.6m

5 0
3 years ago
17. ____ Objects with more mass have
AnnZ [28]

a. more gravity

This is the answer.

5 0
3 years ago
A typical adult human has a mass of about 70 kg.
Misha Larkins [42]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2 
<span>= 2.40 x 10-3 N

b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N 
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
3 0
3 years ago
A 1.0-kg block and a 2.0-kg block are pressed together on a horizontal frictionless surface with a compressed very light spring
Lunna [17]

Answer:

statement B is true

Explanation:

since same force is applied by the compressed spring on both masses so their rate of change of momenta must be same and since the lighter block has lesser mass so it must have greater velocity to have an equal change in momentum as of heavier mass.

By relation: KE=\frac{(mv)^{2} }{2m}

KE lighter=\frac{(mv)^{2} }{2(1)} , KEheavier=\frac{(mv)^{2} }{2(2)}

comparing momenta of above two equations we get

KElighter (2) = KEheavier (4)

KElighter = 2 KEheavier

7 0
4 years ago
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