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ch4aika [34]
3 years ago
13

*please please help* Suppose you are going on a car trip with your family.

Physics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

1. To determine the average speed for the first day of the trip, the total distance traveled would have to be acquired and then how long it took to arrive at the final destination, only including the time that was actually traveled and not any time that was accumulated by any rest stops. Once you have this information, you have to divide the distance over time and you have the average speed (mph).

2. To determine the instantaneous speed, you would just have to look at the speedometer, which tells you at what speed the car is traveling at that exact moment.

Explanation:

I took physics 121 and got the same question. This is my answer that i used and my teacher said it was right.

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A hydraulic lift consists of two pistons that connect to each other by an incompressible fluid. If one piston has an area of 0.1
hjlf
You have:
 
 A1= 0.15 m²
 A2=6.0 m²
 F1=130.0 N
 
 To solve this problem you must use the pressure formula, as below:
 
 P1=P2
 F1/A1=F2/A2
 
 Then, you have:
 
 m2=A2xF1/A1xg
 
 g=9.81 m/s² (This is the acceleration of gravity)
 
 When you substitute the values in m2=A2xF1/A1xg, you obtain:
 
 m2=(0.60 m² x 130.0 N)/(0.15 m² x 9.81 m/s²)
 
 The answer is:
 
 m2=530 Kg
5 0
4 years ago
A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0
sergey [27]

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=\frac{1}{2}m(v^2-u^2)

Using the formula

Work done, W=\frac{1}{2}(0.145)((25)^2-0)

Work done=\frac{1}{2}(0.145)(625)

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

3 0
3 years ago
How do I solve this???
Naya [18.7K]

The projectile maintains its horizontal component of speed because there's nothing exerting any horizontal force on it. <em>(b) </em>

Gravity has no effect on horizontal motion.

4 0
3 years ago
Read 2 more answers
A 20-kg child is on top of a slide was pushed down by his brother giving him an initial speed of 2 m/s down the slide. what is t
Andrews [41]

Answer:

please find your answer in the attached picture, along with explanation.

4 0
3 years ago
3. a car takes off with initial velocity of 20m/s and move with uniform acceleration of 12m/s2 for 20s. It maintained a constant
lions [1.4K]

The total distance traveled by the car at the given velocity and time is 900 m.

The given parameters:

  • <em>initial velocity of the car, u = 20 m/s</em>
  • <em>acceleration of the car, a = 12 m/s²</em>
  • <em>time of motion of the car, t = 20 s</em>
  • <em>final time = 30 s</em>
  • <em>final acceleration = 2 m/s²</em>

The final time of motion of car before coming to rest is calculated as follows;

v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s

The graph of the car's motion is in the image uploaded.

The total distance traveled by the car is calculated as follows;

total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m

Thus, the total distance traveled by the car at the given velocity and time is 900 m.

Learn more about velocity-time graph here: brainly.com/question/24874645

3 0
3 years ago
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