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faltersainse [42]
3 years ago
9

Will give brainlist if answer question!

Physics
1 answer:
ella [17]3 years ago
8 0

Answer:

DE LA SEGUNDA LEY DE NEWTON

Explanation:

<em>m</em> = 16000 N/5.0 m/s^{2} = 3200 kg

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Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
Mila [183]

Explanation:

Formula to determine the critical crack is as follows.

          K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}

  \gamma = 1,     K_{IC} = 24.1

  [/tex]\sigma_{y}[/tex] = 570

and,   \sigma_{f} = 570 \times \frac{3}{4}

                       = 427.5

Hence, we will calculate the critical crack length as follows.

      a = \frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}

        = \frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}

       = 10.13 \times 10^{-4}

Therefore, largest size is as follows.

            Largest size = 2a

                                 = 2 \times 10.13 \times 10^{-4}

                                 = 20.26 \times 10^{-4}

Thus, we can conclude that the critical crack length for a through crack contained within the given plate is 20.26 \times 10^{-4}.

4 0
3 years ago
PLEASE HELP ME WILL GIVE BRAINLIEST
weqwewe [10]

Answer:

A.always changing

Explanation:

7 0
2 years ago
Read 2 more answers
I need help on all of them
oksano4ka [1.4K]
Your attachment won’t load.
6 0
2 years ago
You are designing a delivery ramp for crates containing exercise equipment. The 1890 N crates will move at 1.8 m/s at the top of
Mashcka [7]

Answer:

K = 588.3 N/m

Explanation:

From a forces diagram, and knowing that for the maximum value of K, the crate will try to rebound back up (Friction force will point downward):

Fe - Ff - W*sin(22) = 0    Replacing Fe = K*X   and then solving for X:

X = \frac{Ff + W*sin(22)}{K}=\frac{1223}{K}

By conservation of energy:

\frac{K*X^{2}}{2}-mg*d*sin(22)-\frac{m*V^{2}}{2}=-Ff*d

Replacing our previous value for X and solving the equation for K, we get maximum value to prevent the crate from rebound:

K = 588.3 N/m

6 0
3 years ago
What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, start
Llana [10]

Answer:

v_f=41.65\frac{m}{s}

Explanation:

The final velocity is given by the following kinematic equation:

v_f=v_0+at

Here, v_0 is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

7.5min*\frac{60s}{1min}=450s

Now, we calculate the final velocity:

v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}

4 0
3 years ago
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