<span>B. Energy is never created nor destroyed.
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The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
Learn more about force here:
brainly.com/question/25573309
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Answer: charge Q = 40Coulombs
Explanation: The current in a circuit is the quantity of charge that flows through it per second.
Here the 2amp current is same as the amount of charge in coulomb that flows through the terminal in ONE second.
So, if 2 coulomb of charge flows in 1sec then in 20 secs we will have
Q(charge) = 2*20 = 40 coulombs
Hooke's law is stated as: F = -kx
Where:
F = Force to compress or extend a spring (unit N)
k = Spring constant
x = displacement of spring
Or to help you in your native language:
<span>F = adalah gaya
</span><span>k = adalah konstante pegas
</span><span>x = adalah jarak pergerakan pegas dari posisi normalnya</span>
The answer is c to take a pictures with the camera in the metal hall
