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bagirrra123 [75]
3 years ago
15

One pot has a water height of 8cm. Calculate the water pressure at the bottom of the pot. They give g = 10N / kg p = 1000kg / m3

Physics
1 answer:
natima [27]3 years ago
5 0

Answer:

P = 800 Pa

Explanation:

The pressure of water at the bottom of the pot can be given by the following formula:

P = \rho g h

where,

P = Pressure at the bottom of the pot = ?

ρ = density = 1000 kg/m³

h = height of water = 8 cm = 0.08 m

Therefore,

P = (1000\ kg/m^3)(10\ m/s^2)(0.08\ m)

<u>P = 800 Pa </u>

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Removing the radiator cap is advisable as it will help release steam and cool an overheated engine quicker.
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Answer:

False.

Explanation:

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compare 51.5 hectograms to 51500 decigrams. How do each of these values compare to a gram, and which represents a larger mass?
Olin [163]
These values when compared seem to be the same. They are equal. If we convert them to the same units, they results to the value which is:
 
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7 0
3 years ago
A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above
nydimaria [60]

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

Explanation:

From the question we are told that

   The mass of the rock is  m = 0.250 \ kg

    The length of the string is  L = 0.75 \  m

    The angle the string makes horizontal is  \theta  = 11.9^o

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  \phi = 34.6^o

    The angular velocity of the rock is  w = 2.50 rev/s  = 2.50 * 2\pi  =15.7 \ rad/s

Generally the radius of the circle made by the length of the string is mathematically represented as

               r = L cos(\theta )

=>            r = 0.75  cos(11.9 )

=>            r = 0.734 \ m

Generally the resultant tangential velocity is mathematically represented as

      v__{R}}  = w * r

=>  v__{R}}  = 15.7  *0.734

=>  v__{R}}  =  11.5 \ m/s

Generally the tangential velocity along the x-axis is  

      v_x  = -v__{R}} *  sin(\phi)

=>   v_x  =- 11.5 *  sin(34.6)

=>   v_x  = -6.543 \ m/s

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      v_y = v__{R}} *  cos(\phi)

=>   v_y  = 11.5 *  cos(34.6)

=>   v_y  = 9.47 \ m/s

Generally the tangential velocity along the y-axis is  

      v_z = v__{R}} *  cos(90)

=>   v_z = 0 \ m/s

Generally the tangential velocity at that instant is mathematically represented as

       v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

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3 years ago
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