If 0.583 g of ammonia (NH3) is dissolved to make 250 mL of solution, what is the molarity?
1 answer:
Answer:
0.137 M NH3
Explanation:
First divide the mass of NH3 by the molar mass of NH3, and then divide by the volume to get molarity.
0.583 g / 17.031 g/mol = 0.0342 mol NH3
0.0342 mol NH3 / 0.250 L = 0.137 M NH3
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The pressure in the flask is 3.4 atm.
<em>pV</em> = <em>nRT
</em>
<em>T</em> = (20 + 273.15) K = 293.15 K
<em>p</em> = (<em>nRT</em>)/<em>V</em> = (1.4 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 293.15 K)/10 L = 3.4 atm
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