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Aloiza [94]
3 years ago
9

If 0.583 g of ammonia (NH3) is dissolved to make 250 mL of solution, what is the molarity?

Chemistry
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

0.137 M NH3

Explanation:

First divide the mass of NH3 by the molar mass of NH3, and then divide by the volume to get molarity.

0.583 g / 17.031 g/mol = 0.0342 mol NH3

0.0342 mol NH3 / 0.250 L = 0.137 M NH3

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ikadub [295]

Answer:

A balloon

A bottle of soda

A rock

A water bottle

Explanation:

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3 years ago
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How many atoms are in 2.10 g of K? molar mass of K=39.10g/mole.
Alborosie

Answer:

<h3>The answer is option B</h3>

Explanation:

To calculate the number of atoms we must first calculate the number of moles

Molar mass = mass / number of moles

number of moles = mass / Molar mass

Molar mass (K) = 39.10mole

mass = 2.10g

number of moles = 2.10/ 39.10

= 0.0537mol

After that we use the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10^23 entities

Number of K atoms is

N = 0.0537 × 6.02 × 10^13

<h3>N = 3.23×10^22 atoms of K</h3>

Hope this helps you.

5 0
3 years ago
Number of sodium atom(s) in salt (NaCl)
asambeis [7]

Answer:

NaCl consists of one atom each of sodium and chlorine. Hence, each molecule of NaCl has 2 atoms total.

Explanation:

6 0
3 years ago
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Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce
levacccp [35]

The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca^{2+}(aq) and 0.0390 M Ag^{+}(aq). What will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate? What percentage of the Ca^{2+}(aq) can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

      Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}

[Ag^{+}] = 0.0390 M

When Ag_{2}SO_{4} precipitates then expression for K_{sp} will be as follows.

         K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]

        1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]

       [SO^{2-}_{4}] = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

         CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}

      K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

     4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788

           [Ca^{2+}] = 0.00625 M

Now, we will calculate the percentage of Ca^{2+} remaining in the solution as follows.

               \frac{0.00625}{0.05} \times 100

                 = 12.5%

And, the percentage of Ca^{2+} that can be separated is as follows.

                     100 - 12.5

                     = 87.5%

Thus, we can conclude that 87.5% will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate.

4 0
3 years ago
An atom of Fe has 30 neutrons. What is the mass number of this atom?
SVETLANKA909090 [29]

Answer:

56

Explanation:

The mass number of an atom is a sum of its number of protons and neutrons. Iron (Fe) has an atomic number of 26. This means that it has 26 protons. Since we know it has 26 protons and are told it has 30 neutrons. The mass number of this atom of Iron is 26+30 = 56

Hope this helped!

7 0
3 years ago
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