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3 years ago

The greater the mass is in an object, the higher resistance to a change in movement the object will have.

Physics

2 answers:

gavmur [86]3 years ago

7 0

The correct answer is True

Explanation:

According to Newton's first law about motion, objects or bodies show a resistance to change their state this includes static objects or those that move. In this way, an object will not change its movement or state except if forces act on it, this is commonly known as inertia. Additionally, inertia and mass (quantity of matter) are closely related as the greater the mass the higher resistance, this can be explained as greater external forces are necessary to change the state of the object if the mass is greater. Thus, it is true the greater the mass is in an object, the higher the resistance to a change in movement the object will have.

Bond [772]3 years ago

3 0

True. Since Inertia states this law, we are bound to believe greater mass = greater resistance in change of motion

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alexandr402 [8]

Option A is the correct answer.

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3 years ago

A horizontal net force F is exerted on an object at rest. The object starts at x=0 m and has a speed of 4.0 m/s after moving 4.0

Alex_Xolod [135]

Explanation:

The solution is be found in the attachment.

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3 years ago

A 2. 0 μf and a 4. 0 μf capacitor are connected in series across an 8. 0-v dc source. what is the charge on the 2. 0 μf capacito

Nezavi [6.7K]

voltage across 2.0μf capacitor is 5.32v

Given:

C1=2.0μf

C2=4.0μf

since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

$c = \frac{c1 \times c2}{c1 + c2}$

$= \frac{2 \times 4}{2 + 4}$

=1.33μf

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

Q=CV

given,V=8v

$= 1.33 \times 10 {}^{ - 6} \times 8$

$= 10.64 \times 10 {}^{ - 6}$

charge on 2.0μf capacitor is

$\frac{Qeq}{2 \times 10 {}^{ - 6} }$

$= \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} }$

=5.32v

learn more about series capacitance from here: brainly.com/question/28166078

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3 0

2 years ago

In a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0° above the horizon

Masja [62]

Answer:38.66 m

Explanation:

Given

launch angle $\theta =51^{\circ}$

launch velocity $u=18 m/s$

center of mass continue to travel its original Path so it center of mass will be at a distance of

$R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{18^2\sin 102}{9.8}$

$R=32.33 m$

Center of mass will be at $x=32.33 m$

(b)if one of the piece will be at x=26 m then other will be at

$x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$

$x_{com}=\frac{\frac{m}{2}\cdot 26+\frac{m}{2}\cdot x_0}{\frac{m}{2}+\frac{m}{2}}$

$32.33=\frac{26+x_0}{2}$

$x_0=38.66 m$

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3 years ago

A crane raises a crate with a mass of 150 kg to a height of 20 m. Given that

Virty [35]

Answer:

$\boxed {\boxed {\sf 29,400 \ Joules}}$

Explanation:

Gravitational potential energy is the energy an object possesses due to its position. It is the product of mass, height, and acceleration due to gravity.

$E_P= m \times g \times h$

The object has a mass of 150 kilograms and is raised to a height of 20 meters. Since this is on Earth, the acceleration due to gravity is 9.8 meters per square second.