Answer:
Total distance= 250miles
Displacement= 206.15 miles
Explanation:
Step one:
given data
A car drives 200 miles east
Turns and travels 50 miles north
Step two:
The total distance travelled= 200+50= 250 miles
The displacement
S^2= 50^2+200^2
S^2= 2500+40000
S^2=42500
S=√42500
S=206.15 miles
Answer:
(a). The angular speed of the rotating is 33.8 rad/s.
(b). The speed of its center is 2.7 m/s.
Explanation:
Given that,
Radius = 8.00 cm
Mass = 0.180 kg
Height = 75.0 m
We need to calculate the angular speed of the rotating
Using conservation of energy
Here, initial velocity and angular velocity are equal to zero.
Here, 
The angular speed of the rotating is 33.8 rad/s.
(b). We need to calculate the speed of its center
Using formula of speed
Put the value into the formula
Hence, (a). The angular speed of the rotating is 33.8 rad/s.
(b). The speed of its center is 2.7 m/s.
Answer:
66.375 x 10⁻⁶ C/m
Explanation:
Using Gauss's law which states that the net electric flux (∅) through a closed surface is the ratio of the enclosed charge (Q) to the permittivity (ε₀) of the medium. This can be represented as
;
∅ = Q / ε₀ -----------------(i)
Where;
∅ = 7.5 x 10⁵ Nm²/C
ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²
Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;
7.5 x 10⁵ = Q / (8.85 x 10⁻¹²)
Solve for Q;
Q = 7.5 x 10⁵ x 8.85 x 10⁻¹²
Q = 66.375 x 10⁻⁷ C
Now, we can find the linear charge density (L) which is the ratio of the charge(Q) to the length (l) of the rod. i.e
L = Q / l ----------------------(ii)
Where;
Q = 66.375 x 10⁻⁷ C
l = length of the rod = 10.0cm = 0.1m
Substitute these values into equation (ii) as follows;
L = 66.375 x 10⁻⁷C / 0.1m
L = 66.375 x 10⁻⁶ C/m
Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.
