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arsen [322]
3 years ago
10

Help me with these questions :)

Chemistry
1 answer:
maxonik [38]3 years ago
3 0

Answer:

1 ) H2O 2) Hydrogen and oxygen 3) Compound

Explanation:

1) To write a chemical formula, you write the number of molecules of an element (2 hydrogen atoms + 1 Oxygen atom, or H2O). The letters represent the element's notation on the periodic table, while the number that follows it represents the number of atoms of that particular element within the compound. If there is no number that follows the letter, there is only one.

2) Letter "H" on the periodic table represents hydrogen, while "O" represents oxygen

3) You can tell that this is a compound because it is made of two or more elements found on the periodic table

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Answer:

Food and cell type

Explanation:

Kingdoms are by far the most basic legal structure for living objects. Living objects are classified into realms depending on how they consume food, the kinds of cells that produce their bodies, and the total type of tissue in their bodies.

6 0
2 years ago
What factor, according to the data in the table above, has the greatest impact on species loss?
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B. The area of the island is your answer :)
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Which of the following is NOT a property of an acid
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The answer is B. Acid turns blue litmus paper to red
4 0
2 years ago
Chemistry Question, Don't really know how to do it lol.
Scilla [17]

Answer: 17.2 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} HgS=\frac{20.0 g}{233g/mol}=0.085moles

The balanced chemical equation is:

4HgS(s)+4CaO(s)\rightarrow 4Hg(l)+3CaS(s))+CaSO_4(s)  

According to stoichiometry :  

4 moles of HgS produce =  4 moles of Hg

Thus 0.085 moles of HgS will require=\frac{4}{4}\times 0.085=0.085moles  of Hg

Mass of Hg=moles\times {\text {Molar mass}}=0.085moles\times 200.6g/mol=17.2g

Thus 17.2 g of Hg will be produced form 20.0 g of HgS.

3 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
krok68 [10]

Answer:

\large \boxed{\text{2.20 g Pb}}

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:       239.27   32.00        207.2

            2PbS   +   3O₂   ⟶  2Pb   +   2SO₃

m/g:      2.54        1.88

2. Calculate the moles of each reactant

\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}

3. Calculate the moles of Pb from each reactant

\textbf{From PbS:}\\\text{Moles of Pb} =  \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol  Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}

4. Calculate the mass of Pb

\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}

5 0
2 years ago
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