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Scilla [17]
4 years ago
14

Water can dissolve almost anything in the universe

Physics
1 answer:
Elodia [21]4 years ago
5 0

Answer:

No, its not possible for water to dissolve almost anything in the universe.

Explanation:

Solubility of a solute defines the ability of that solute to dissolve in a given solvent. It is defined as the maximum amount of solute dissolved in a solvent at equilibrium. The solution which results from dissolving this maximum amount is called a saturated solution, and one it has been reached, no more solute can be dissolved in it.

Different substances in the universe have diffferent solubilities in water, some very high (soluble) (eg. sugar and salt) and some very low (insoluble) (eg plastics). The substances that are able to form bonds with water (Hydrogen or Ionic) are more soluble than those who are not able to do so.

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If energy is continually added to a gas, what will it likely become?
tamaranim1 [39]
The gas will remain a gas and the energy will be transformed into heat raising the temperature
(Some very rare exceptions might occur)
5 0
3 years ago
A person yells across a canyon and hears an echo 2.5 seconds later. The air temperature is 21°C. How far away is the canyon wall
Alchen [17]

Answer: The canyon wall is 850 m away from the person

Explanation:

Well, the speed of sound V in air at 21 \° C is defined as 343.60 m/s, this can be calculated by the following equation:

V=\sqrt{\frac{\gamma R T}{M}} (1)

Where:

\gamma=1.4 is the Heat capacity ratio for air

R=8.314 J/mol.K is the Universal Gas constant

T=21 \° C+273.15=294.15 K is the temperature in Kelvin

M=0.029 kg/mol is the air molar mass

V=\sqrt{\frac{(1.4)(8.314 J/mol.K)(294.15 K)}{0.029 kg/mol}}

V=343.60 m/s (2)

Now that we know the speed of sound, we can use the following equation to find the distance between the person and the canyon wall:

V=\frac{d}{t} (3)

Where:

d is the distance between the person and the canyon wall

t=2.5 s is the time it takes to the sound wave to travel from the person and then go back

Isolating d:

d=V.t (4)

d=(343.60 m/s)(2.5 s) (5)

Finally:

d=850 m

7 0
3 years ago
A Van de Graaff generator causes a total charge q to build up on a metal sphere of radius r. Which variable does not affect the
Maru [420]

Answer:

The radius r of the metal sphere.

Explanation:

From Gauss's law we know that for a spherical charge distribution with charge Q, the electrical field at distance R from the center of the sphere is given by

E=\frac{Q}{4\pi \epsilon_oR^2}

What is important to notice here is that the radius of the sphere does not matter because any test charge sitting at distance R feels the force as if all the charge Q were sitting at the center of the sphere.

This situation is analogous to the gravitational field. When calculating gravitational force due to a body like the sun or the earth, we take not of only the mass of the sun and the distance from it's center; the sun's radius does not matter because we assume all of its mass to be concentrated at the center.

6 0
3 years ago
If a force does a positive amount of work on an object, does the object’s speed increase, decrease, or remain the same? Justify
iris [78.8K]

Answer:

see that there is no dependence on speed, so the work remains constant

Explanation:

Work is defined by the expression

        W = F. d

where the boldface indicates vectors, this equation can be written in scalar form

         W = f d cos θ

where θ is the angle between force and displacement.

We see that there is no dependence on speed, so the work remains constant

The power is

           P = W / t

           P = f d / t

           p = F v

we see that the power is the one that depends on the speed of the body

6 0
3 years ago
1. Identify the significance of the following terms to the subject of the Civil War.
DanielleElmas [232]
What following terms I don’t see any please make your question clear
4 0
4 years ago
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