Answer:
0.0078 N
Explanation:
The electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
The force is attractive if the two charges have opposite sign, and repulsive if the two charges have same sign.
In this problem, we have:
located at 
located at 
located at 
The force between charge 1 and charge 2 is:

And since the two charges have opposite sign, the force is attractive, so the force on charge 1 is towards the right.
The force between charge 1 and charge 3 is:

And since the two charges have same sign, the force is repulsive, so the force on charge 1 is towards the left.
Therefore, the net force on charge 1 is:

towards the right.
Answer:
a) v = 5.59x10³ m/s
b) T = 4 h
c) F = 1.92x10³ N
Explanation:
a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:


Where:
g is the gravity = 9.81 m/s²
r: is the Earth's radius = 6371 km
h: is the satellite's height = r = 6371 km
b) The period of its revolution is:
c) The gravitational force acting on it is given by:

Where:
M is the Earth's mass = 5.97x10²⁴ kg
m is the satellite's mass = 782 kg
G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

I hope it helps you!
Hello! Light waves are an example of electromagnetic waves. I hope this helps!
Answer:
speed is 81.03 mph
direction is N 3.58 W
Explanation:
given data
travel north = 70 mph
Stream current = 12 mph
direction = S 25° E
result due north = 70 mph
to find out
speed and direction
solution
we will get component of resultant that is
v cosθ and v sinθ
so
( 12cos295 , 12 sin295 ) at ( 0, 70)
as that we can say
v sinθ + 12sin295 = 70 ....................1
v cosθ + 12 cos295 = 0 ......................2
so
vcosθ = -5.0714
vsinθ = 80.8756
now by ratio
cosθ /sinθ = -5.0714/ 80.8756
cot θ = -0.0627
θ = 93.58
so direction is N 3.58 W
and
we know
vcosθ = - 12cos295
v = - 12cos295 / cos(93.58)
v = 81.03 mph
so speed is 81.03 mph
The force between two parallel wires carrying currents in the same direction is attractive. It is repulsive if the currents are in opposite directions.