Answer:
20,000,000 N
Explanation:
First find the acceleration:
a = Δv / Δt
a = (0 − 40 m/s) / 0.010 s
a = -4000 m/s²
Next use Newton's second law to find the force on the car:
F = ma
F = (5000 kg) (-4000 m/s²)
F = -20,000,000 N
According to Newton's third law, the force on the wall is equal and opposite the force on the car.
F = 20,000,000 N
Answer: 2.9kg
let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.
represent the mass. By resolving forces, we have:
F=mgSin(theta)
15N=mgSin(32°)
m=15N/g×Sin(32°)
m=15N/9.8m/s^2÷Sin(32°)
=2.888kg2.888
≈2.9kg
Sounds like the situation is modeled like so:
[Light] - - - - - - - - - - [You] => - - -
- - - - - - - - - - - - - - - [Cop] - - - - -
<= = = 200 m = = =>
where your velocity is 27.8 m/s to the right. So the question is asking, is it possible that your car, given that it accelerates at a maximum of 1/5 m/s^2, can reach a speed of 27.8 m/s from rest in the time it takes for it to cover 200 m.
The car's position at time 
is
The time it takes to traverse 200 m is
Your car's velocity at time , starting from rest, is
so that after 16.3 s, your car is moving at a speed of
which is less than the speed the cop claims you were going, so the cop is not correct.
Answer:
|q1|/|q2| = 1/7
Explanation:
Particle 1 experiences a force F1 due to the magnetic field, B:
F1 = |q1|*v1*B
Particle 2 experiences a force F2 due to the magnetic field, B:
F2 = |q2|*v2*B
We're given that:
v1 = 7v2
Also, the force experience by both particles are equal:
F1 = F2
=> |q1|*v1*B = |q2|*v2*B
|q1|/|q2| = v2/v1
=> |q1|/|q2| = v2/7v2
=> |q1|/|q2| = 1/7
False, Gamma Rays are the smallest because gamma rays have the shortest wave length
