Question

An experiment calls for 0.0284 g of potassium hydroxide, KOH. How many milliliters of 0.0200 M KOH are required

Answer 1

Answer:

We need 25.3 mL of KOH

Explanation:

Step 1: Data given

Mass of potassium hydroxide (KOH) = 0.0284 grams

Molarity of KOH = 0.0200 M

Molar mass of KOH = 56.106 g/mol

Step 2: Calculate moles of KOH

Moles KOH = mass KOH / molar mass KOH

Moles KOH = 0.0284 grams / 56.106 g/mol

Moles KOH = 5.06 *10^-4 moles

Step 3: Calculate volume needed

Molarity KOH solution = moles KOH /volume

Volume = moles KOH / molarity KOH

Volume = 5.06 * 10^-4 moles / 0.0200 M

Volume = 0.0253 L = 25.3 mL

We need 25.3 mL of KOH