MATch THE BOXED PLEASEEEE

Chemistry

2 answers:

LiRa [457]3 years ago

8 0

Answer:

Transform = The third one

Convergent = the first one

Divergent = the second one

Explanation:

8090 [49]3 years ago

4 0

Divergent: divide (separate)
convergent: collide
transform: slide past

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A particle with charge +1 nC (a nanocoulomb is 1 10-9 C) is located at the origin. What is the electric field due to this partic

Zolol [24]

Answer:

$E=35.97\frac{V}{m}$

Explanation:

The electric field of a point charge can be calculated using the next equation:

$E=\frac{1}{4\pi \epsilon_0} \frac{Q}{r^2}$

Where:

$\epsilon_0=Absolute\hspace{3}permittivity\hspace{3}of\hspace{3}free\hspace{3}space\approx 8.85\times 10^{-12} \\Q=Charge\hspace{3}magnitude\\r=Distance$

The distance can be calculated as:

$r=\sqrt{0.5^2+0^2+0^2} =0.5$

Using the data provided by the problem:

$E=\frac{1}{4\pi (8.85\times 10^{-12}) } \frac{1\times 10^{-9} }{0.5^2} =35.96721878\approx35.97V/m$

8 0

4 years ago

Heeeeeeeeeeeeeeeeeeeeeelp

Genrish500 [490]

Answer:

The correct answer is 2.33g of $H_{2}O$ , A

Explanation:

We can use basic stoich to get this question.

To start, lets convert our grams to moles in order to use our equation. 5.38g of $O_{2} = (\frac{5.38}{2*15.999}) moles = 0.168136$ moles.

We then can use our molar ratio of 13:10. Simply divide by our molar ratio in order to go from moles of $O_{2}$ to moles of $H_{2}O$ . This gets us 0.129335 moles of $H_{2}O$ .