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choli [55]
3 years ago
13

The heat flux that is applied to the left face of a plane wall is q" = 20 w/m2. the wall is of thickness l = 10 mm and of therma

l conductivity k = 12 w/m · k. if the surface temperatures of the wall are measured to be 50°c on the left side and 30°c on the right side, do steady-state conditions exist?
Physics
2 answers:
inessss [21]3 years ago
5 0
Of course steady state condition occurs in almost any system but time it will occurs varies among system. for this kind of system, conduction, steady state conduction occurs when the temperature change from one point to the point is already constant. steady state is not achieved immediately because the heat travels and material will not be heated at the same way at the starting point.
ki77a [65]3 years ago
3 0

Answer:

given flux is very small then the above calculated value so it is not is steady state

Explanation:

As we know that heat flux is given in steady state by the formula

Q = \frac{k(T_1 - T_2)}{L}

here we know that

T_1 = 50^o C

T_2 = 30 ^o C

k = 12 W/m k

L = 10 mm

now we have

Q = \frac{12(50 - 30)}{0.01}

Q = 24000 w/m^2

since given flux is very small then the above calculated value so it is not is steady state

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a brick is suspended above the ground at a height of 6.6 m. it has a mass of 5.3 kg. what is the potential energy of the brick
Svetradugi [14.3K]
The formula for potential energy is
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= 342.8 J

How did I get 9.8?
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8 0
3 years ago
Which of the following statements is true about the scientific process?
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The best and most correct answer among the choices provided by your question is the third choice or letter C.
<span>The statement "Your hypothesis must be testable." is true about the scientific process.


</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the i
Mariana [72]

Answer:

451.13 J/kg.°C

Explanation:

Applying,

Q = cm(t₂-t₁)............... Equation 1

Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.

Make c the subject of the equation

c = Q/m(t₂-t₁).............. Equation 2

From the question,

Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C

Substitute these values into equation 2

c = 1500/[0.133(45-20)]

c = 1500/(0.133×25)

c = 1500/3.325

c = 451.13 J/kg.°C

4 0
3 years ago
A formula for the normal systolic blood pressure for a man age a , measured in mmhg, is given as p=0. 006a2−0. 02a 120. Find the
djyliett [7]

The age of a man whose normal blood pressure measures 123 mm of hg

9 years

<h3>What is Quadratic equation ?</h3>

A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = ax^{2} + bx + c, where a, b, and c are numbers and a cannot be 0

P(A) = 0.006 a^{2} - 0.02a + 120

123 = 0.006- 0.02a + 120

0=0.006 a^{2} - 0.02a - 3

you can use the quadratic equation  formula to solve for the man's age.

A = (-b ± (\sqrt{b^{2} - 4*a*c})  ) / (2a)

A = (0.02 ±  \sqrt{(-0.02)^{2} - 4*0.006*(-3)}/ (2*0.006)

A = (0.02 ± \sqrt{0.0076}) / 0.012

A = 9 , -5.67

Age of the man will be 9 years

To learn more about quadratic equation  here

brainly.com/question/17177510?referrer=searchResults

#SPJ4

5 0
2 years ago
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