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choli [55]
3 years ago
13

The heat flux that is applied to the left face of a plane wall is q" = 20 w/m2. the wall is of thickness l = 10 mm and of therma

l conductivity k = 12 w/m · k. if the surface temperatures of the wall are measured to be 50°c on the left side and 30°c on the right side, do steady-state conditions exist?
Physics
2 answers:
inessss [21]3 years ago
5 0
Of course steady state condition occurs in almost any system but time it will occurs varies among system. for this kind of system, conduction, steady state conduction occurs when the temperature change from one point to the point is already constant. steady state is not achieved immediately because the heat travels and material will not be heated at the same way at the starting point.
ki77a [65]3 years ago
3 0

Answer:

given flux is very small then the above calculated value so it is not is steady state

Explanation:

As we know that heat flux is given in steady state by the formula

Q = \frac{k(T_1 - T_2)}{L}

here we know that

T_1 = 50^o C

T_2 = 30 ^o C

k = 12 W/m k

L = 10 mm

now we have

Q = \frac{12(50 - 30)}{0.01}

Q = 24000 w/m^2

since given flux is very small then the above calculated value so it is not is steady state

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shutvik [7]

Answer:

The speed of the faster ship is 22.5 m/s

Explanation:

The length of the ships are;

Ship 1 = 200 m

Ship 2 = 100 m

The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds

The time it takes both ships to cross each other when travelling in the same direction = 25 seconds

Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;

(x + y) × 10 = 200 + 100 = 300

10·x + 10·y = 300...(1)

(x - y) × 20 = 200 + 100 = 300

20·x - 20·y = 300...(2)

Multiply equation (1) by 2, to get;

(x + y) × 10 × 2 = 300 × 2

20·x + 20·y = 600...(3)

Adding equation (1) to equation (3) gives;

20·x + 20·y + 20·x - 20·y = 600 + 300

40·x = 900

x = 900/40 = 22.5

x = 22.5

The speed of the first ship, ship 1 = x = 22.5 m/s

From equation (1), we have;

10·x + 10·y = 300

y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5

y = 7.5

The speed of the second ship, ship 2 = y = 7.5 m/s

Therefore, the faster ship is ship 1 with a speed of 22.5 m/s

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2 years ago
A+20 N force acts on a car and at the same time, a -30 N force acts on the
katovenus [111]

Answer:

-10 N, not balanced

Explanation:

Force is a vector quantity, so in order to find the net force on an object, we must use vector addition rule.

This means that if two forces acting on an object along the same line, we have to choose one direction as positive, and write the two forces with the correct sign.

In this problem, we have two forces acting along a line on the car:

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Therefore, the net force on the car is:

\sum F=F_1+F_2=+20 +(-30)=-10 N

Moreover, the net force on an object is said to be "balanced" if it is zero: in this case, it is not zero, so it is not balanced.

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