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SSSSS [86.1K]
3 years ago
5

Which of these is an example of the meaning of inertia in physics

Physics
1 answer:
Vladimir79 [104]3 years ago
6 0
The correct option is A.
In physics, inertia has to do with Newton's first law of motion which states that an object will continue in its state of rest or in motion unless it is acted upon by a force. Thus, inertia refers to the tendency of an object to continue its motion in a straight line at constant velocity. In the question given above, the car that its brake failed would have continue moving indefinitely if it did not crash into another car, that is, it will continue in its state of motion.
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3 years ago
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Can someone help me?!!!!!
german
<h2>Hello!</h2>

The answer is:

The first option,  the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

Distance=NorthCoveredDistance+EastCoveredDistance

Distance=4*180m+3*180m=720m+540m=1260m

Actual distance between the start and the end point (displacement):

ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

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3 0
3 years ago
The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A
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Answer:

2.1\times 10^{-12} c

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We have to find the charge resides on the outer surface of membrane.

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C=\frac{k\epsilon_0 A}{d}

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Capacitance between parallel plate capacitor=\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}

C=0.25\times 10^{-12}F

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Q=CV

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Hence, the charge resides on the outer surface=2.1\times 10^{-12} c

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