Question

How many atoms of sulfur, S, are in 4.00 g sulfur?

Answer 1

Answer:

7.51 × 10²² atoms S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

4.00 g S

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of S - 32.07 g/mol

Step 3: Convert

1. Set up:                              $\displaystyle 4.00 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})(\frac{6.022 \cdot 10^{23} \ atoms \ S}{1 \ mol \ S})$
2. Multiply:                            $\displaystyle 7.51107 \cdot 10^{22} \ atoms \ S$

Step 4: Check

Follow sig figs and round. We are given 3 sig figs.

7.51107 × 10²² atoms S ≈ 7.51 × 10²² atoms S