55.80 C/12= 4.65/2.3225= 2
7.04 H/1= 7.04/2.3225= 3
37.16 O/16= 2.3225/2.3225= 1
Empirical Formula= C2H3O
301.35/43= 7
(C2H3O)7= C14H21O7= Molecular Formula
Answer to the question
D. Petroleum
ok thank you for elaborating and you are correct in a neutralization reaction the reactants are the acid and base. the salt and water would be the product and the two elements could be anything meaning that it is most likely a mixture
Hope this helps
