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Natalka [10]
3 years ago
10

Can someone help me with questions 14,18,16??

Mathematics
1 answer:
Masja [62]3 years ago
3 0

Answer:

13  all three angles =60 in total they equal 180

14) I believe x = 32.5 Am not sure though.

Step-by-step explanation:

That is the only question i can answer but to help you with this all triangles big or small the total of all the angles combined = 180

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Answer 16., 17., and 18., Text me after you have..!
musickatia [10]
I'm not quite sure how I'd attach a picture of my working so I'll explain the method.

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4 0
3 years ago
There are 84 students in the glee club there are 12 more boys than girls what is the ratio of the number of girls to the number
Masja [62]
Let us denote the number of boys in the glee club with X and the number of girls with Y.There are 84 students in the glee club, which means that the following equation can be written:X+Y=84We also now that there are 12 more boys than girls, so:X=Y+12We can rewrite the first equation like:(Y+12)+Y=842Y+12=842Y=62Y=62/2=31X=31+12=43So, the ratio of the number of girls to the number of boys is: Y/X=31/43
Read more on Brainly.com - brainly.com/question/4711779#readmore
5 0
3 years ago
-5a to the second power-7a
kakasveta [241]
-5a^2 - 7a = -a x (5a + 7)
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7 0
4 years ago
Chase has been playing a game where he can create towns and help his empire expand. Each town he has allows him to create 1.13 t
riadik2000 [5.3K]

Well the way I see it is he started with 4 villager so I would see the equation to be

 1.13x times 17+4 would equal the amount of villagers he could have which would be 23.21 as for the equation it would be 1.13x times 17 plus four equals the number of villagers total

7 0
3 years ago
T F IfA and B are similar matrices, then AT=BT
muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices A and B exists an invertible matrix P for which

[tex]B = P^{-1} AP[/tex]

∴ B^{T} = (P^{-1})^{T} A^{T} P^{T} \\

Also P^{-1}P = I\\

and (P^{-1})^{T} = (P^{T})^{-1}

∴(P^{-1})^{T}P^{T} = I

so, B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}

7 0
3 years ago
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