Answer:
b consumers eat producers
Explanation:
In a food chain, the consumers are living organisms that eat organisms from a different population. Examples are herbivores like goats.
Producers make their own food in the food chain. Examples are plants.
The relationship between consumer and producers is hence that consumers consume / eat producers. Goats eat grass.
The correct option is;
b consumers eat producers
I would wager a guess that you're talking about microlattice.
Answer:
- What is the limiting reactant?: HCl is the limitng reactant.
- How many moles of H₂ are formed?: 6.5 moles of H₂ are formed.
Explanation:
Part A: <em>what is the limiting reactant?</em>
1) <u>Balanced chemical equation</u>: given
- 2Al + 6HCl → 2AlCl₃ + 3H₂
2)<em> </em><u>Stoichiometric mole ratio:</u>
Use the coefficients of the balanced equation:
- 2 mol Al : 6 mol HCl : 2 mol AlCl₃ : 3H₂
3) <u>Compare the stoichiometric mole ratio of the reactants with their actual ratio</u>:
- Theoretical ratio: 2 mol Al / 6 mol HCl ≈ 0.33 mol Al / mol HCl
- Actual ratio: 6.0 mol Al / 13 mol Cl ≈ 0.46 mol Al / mol Cl
Since the actual ratio indicates that there is a greater number of moles of Al (0.46) per mol of Cl than what is required by the stoichiometric ratio(0.33), Al is in excess and HCl is the limiting reactant.
Answer: the limiting reactant is HCl.
Part B. <em>How many moles of H₂ are formed?</em>
3. <u>Determine how many moles of H₂ can be formed</u>
- Theoretical ratio using limiting reactant:
6 mol HCl / 3 mol H₂ = 13 mol HCl / x
⇒ x = 13 mol HCl × 3 mol H₂ / 6 mol HCl = 6.5 mol H₂.
The answer must be reported with two significant digits, such as the data are given.
Answer: 6.5 moles of H₂ are formed
Answer:
for given question is 2.79 and
is 0.52
{i- vant hoff’s constant ; Kb- constant ; m molarity }
M = no. of moles of the solute present in one kg of solution
Let the weight of amount of solute be “w” and its molecular mass be “M”
Let the mass of the solvent in the given question be “x”




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