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Flauer [41]
3 years ago
11

-

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

(ii) 1 dye

(iii) Food coloring F is insoluble in the solvent

(iv) 'E' and 'H'

(b) Food colouring G

Explanation:

Paper chromatography principle is based on the rates of migration of chemicals across a sheet of paper which are different and it consists of a stationary phase such as the water in the paper and a mobile phase such as the solvent resulting in the partitioning of the components of the mixture across the paper

The solution components are positioned to start in one place from where they migrate and separate out on the chromatography paper

(ii) The number of components into which the food colouring 'H' separates into = 1

Therefore, the number of dyes in food colouring 'H' = 1 dye

(iii) Food coloring 'F' does not move because it is insoluble in the solvent, which is the mobile phase

(iv) The food colouring that contains the dye that is likely to be most soluble in the solvent are does for which the dyes travel furthest, which are;

Food coloring 'E' and 'H'

(b) Using a similar question solution found on 'tutor my self' website, we have;

The R_f values are given as follows;

R_f = \dfrac{Distance \ moved \ by \ dye}{Distance \ moved \ by \ solvent}

The distance moved by the solvent = 5 units

The distance moved by dyes in food colouring 'E' and 'H' = 4 units

The distance moved by dye in food colouring 'G' = 3.3 units

The distance moved by the second dye in food colouring 'E' = 2.7 units

By inspection, we get;

R_f dye in food colouring 'G' = 3.3/5 = 0.66,

Therefore, the dye with R_f value closest to 0.67 is the dye in food colouring 'G'.

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Suppose Highlinium-308 can also undergo positron emission
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4 0
3 years ago
Will someone please help me with numbers 22-26? I would really appreciate it. Thank you.
Naddika [18.5K]
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5 0
3 years ago
The reaction A( g ) ⇌ 2 B( g ) A(g) ⇌ 2 B(g) has an equilibrium constant of K = 0.010 K = 0.010. What is the equilibrium constan
Over [174]

Answer:

K = 10

Explanation:

Using Hess's law, it is possible to obtain the equilibrium constant, K, of a reaction using K of similar reactions. For example:

<em> If A ⇄ B K = X</em>

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2A ⇄ 2B K = X².

Thus, if A(g) ⇄ 2B(g) K = 0.010

2B(g) ⇄ A(g) K = 1 / 0.010; K = 100

B(g) ⇄ A(g) K = √100 = 10

<h3>K = 10</h3>
5 0
3 years ago
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