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2 years ago

The velocity of 200kg object changes from 10m/s to 22m/s in 12 sec.what is the force on the accelerated object?

Physics

1 answer:

Vikentia [17]2 years ago

4 0

Initial velocity (u) = 10 m/s
Final velocity (v) = 22 m/s
Time (t) = 12 s
Mass (m) = 200 Kg
Let the acceleration be a.
By using the equation of motion,

v = u + at, we have

22 m/s = 10 m/s + 12 s × a
or, 22m/s - 10 m/s = 12 s × a
or, 12 m/s = 12 s × a
or, a = 1 m/s^2
Let the force be F.
We know, F = ma
Therefore, the force on the accelerated object (F)
= ma
= (200 × 1) N
= 200 N

Answer:

b) 200 N

Hope you could understand.

If you have any query, feel free to ask.

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The weight of air in a column 1-m2 in cross section that extends from sea level to the top of the atmosphere is?

Sauron [17]

From sea level to the top of the atmosphere, a column of air with a 1-m2 cross section weighs 101,000 N.

To find the answer we have to know about the pressure.

<h3>What is Pressure?</h3>

The pressure at a point on a surface is the thrust acting per unit area around that point.

$Pressure, P=\frac{Thrust}{Area}=\frac{F}{A}$

A particular mass of air is contained in a column that rises from the ocean to the top of the atmosphere. Then,

$P=P_a=1.013*10^5 pascal$

Pa is the atmospheric pressure at the sea level.

By combining both the equations, we get the weight of air,

$\frac{F}{A}=P_a$

$F=W=P_a*A=1.013*10^5*1=101300N$

Thus, we can conclude that, the weight of air in a column 1-m2 in cross section that extends from sea level to the top of the atmosphere is 101300N.

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3 0

9 months ago

Parallel rays of monochromatic light with wavelength 582 nm illuminate two identical slits and produce an interference pattern o

Airida [17]

Answer:

I = 0.56 10⁻⁴ W / m²

Explanation:

Double-slit interference is described by the expression

d sin θ = m λ

if we use trigonometry we can find the angle

tan θ= y / L

how the angles are small

tan θ = sin θ / cos θ = sin θ

sin θ = y / L

we substitute

d y / L = m λ

if we take into account that each slit also produces a diffraction phenomenon, the intensity distribution is the product of the intensity of the slits by the intensity of the diffraction process

I = I₀ cos² (d a) [(sin ba) / ba]²

a = π sin θ /λ

where the separation of the slits and b is the width of the slits

we substitute

I = I₀ [cos (d a)]² [sin ba /ba]²

a = π y / (L λ)

let's reduce the magnitudes to the SI system

λ = 582 nm = 582 10⁻⁹ m

L = 75.0 cm = 75.0 10⁻² m

d = 0.640 mm = 0.640 10⁻³ m

b = 0.434 mm = 0.434 10⁻³ m

Io = 4.40 10⁻⁴ W / m²