It depend on how far it is from the earths base
There is no correct description on that list of choices.
The net force on the charge at the origin is -1.2×10-8
<u>Explanation:</u>
Solving the problem,
- Draw the x-axis and the locations of the given three charges.
- The forces applied on the charge at the origin and there are two of them, and since all the changes are positive, all the forces are repulsive.
- we have the formula, F = kq1Q/r².
- F1 = kq1Q/r²1 = (9.0*109Nm²/C²)(2.2*10^-9C)(3.5*10^-9C)/(1.5m)² = 31*10-9N = 3.1*10-8N. F1 points to the right (+x direction).
- F2 = kq2Q/r²2 = (9.0*109Nm²/C²)(5.4*10^-9C)(3.5*10^-9C)/(2.0m)² = 43*10^-9N = 4.3*10^-8N.
- F2 points to the left (-x direction).
- To find the net force we have to subtract the force F1 and force F2 .
- The net force is F(origin) = F1 - F2 = -1.2×10-8N.
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The 2nd answer is the correct answer
Answer:
0.7 kg m²
Explanation:
F = force exerted applied by muscle in a professional boxer = 2551 N
r = length of lever arm = 3.15 cm = 0.0315 m
α = angular acceleration of the forearm = 115 rad/s²
I = moment of inertia of the boxer's forearm
τ = Torque applied by muscle in a professional boxer
Torque is given as
τ = I α = r F
Inserting the values
I (115) = (0.0315) (2551)
I = 0.7 kg m²
