A) Net force in component form: 
B) Magnitude of the net force: 316.2, direction: 
Explanation:
A)
The three forces given in this problem are:



The three forces are given in component form, where the components with unit vector i is the component along the x-direction, while the components with unit vector j is the component along the y-direction.
In order to find the net force in component form, we just need to add the components of the three forces along each direction. Therefore:
- Along the x-direction:

- Along the y-direction:

So, the net force in component form is

B)
The magnitude of a vector F is given by Pythagorean's theorem:

where in this problem,
is the x-component
is the y-component
Substituting,

The direction instead is given by

where the negative sign means the direction is below the positive x-axis.
Learn more about vector addition:
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Answer:
Make a graph for better visual representation.
Explanation:
Presenting data like that would require someone to see the increase. The best way would be a graph to be shown, to really show the impact by the line going up in the graph.
Answer:
Speed of second car will be 57.17 m/sec
Explanation:
We have given lead car travels = 44 laps
1 laps = 1.34 km = 1340 m
So total distance = 1340×44 = 58960 m
Speed of lead car = 55.9 m/sec
We know that 
As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m
So speed of second car will be 
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