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Alchen [17]
3 years ago
9

Whether an ionic bond or a covalent bond forms, bonds form in order to make newly created substances ________ than the substance

s they were created from.
A) less stable
B) more stable
C) less efficient
D) more efficient
Physics
1 answer:
Nezavi [6.7K]3 years ago
6 0
The answer would be less stable
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A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
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Explanation: Solution

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Gravitational potential energy

U=mgh=500*9.8*50

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A beta particle is a(n):
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A 2.4 m long rod of mass m1 = 14 kg, is supported on a knife edge at its midpoint. A ball of clay of mass m2 = 3.5 kg is dropped
Mashutka [201]

Explanation:

It is known that;

            L_{i} = L_{f}

Now, we need to calculate the value of L, that is, angular momentum.

Therefore,

                   L= mvr

where,   m = mass

              v = velocity

              r = radius

Hence,

               L = m(\sqrt{2gh}) \times r

So,

              L = (2.2 \times (\sqrt{2 \times 9.81 \times 1.4}) \times 0.9)

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7 0
3 years ago
A 0.51-kg metal sphere oscillates at the end of a vertical spring. As the spring stretches from 0.12 m to 0.23 m (relative to it
den301095 [7]

Answer:

487.23 N/m

Explanation:

Given:

mass of metal sphere 'm'= 0.51kg

the spring stretches from 0.12 m to 0.23 m. Therefore,

s_1}= 0.12m and s_{2}= 0.23m

the speed of the sphere decreases from 6.7 to 3.3 m/s. Therefore,

v_{1}= 6.7m/s and v_2}=3.3m/s

In order to find spring constant, we apply law of conservation of energy. i.e

The change of the kinetic energy of sphere is equal to the change of potential energy of the spring.

So, ΔE_{k} = ΔE_{v}

where,

ΔE_{k} = 1/2 m (v_{1}- v_2})²

ΔE_{v}= 1/2 k (s_1} - s_{2})²

1/2 m (v_{1}- v_2})² = 1/2 k (s_{2}- s_1} )²

k= m [ (v_{1}- v_2})²/(s_{2}- s_1} )²

k= 0.51 [(6.7-3.3)²/ (0.23-0.12)²]

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Thus, the spring constant of the spring is 487.23 N/m

5 0
3 years ago
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