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3 years ago

7

If a creature cats Ferrari, with an initial speed of 10 m/s, accelerate at a rate of 50 m/s/s for 3 seconds, what will it's fina

l speed be?

2 answers:

Anton [14]3 years ago

7 0

Vf = x
Vi = 10 m/s
A = 50 m/s²
T = 3

Vf = Vi + at

x = 10 + 50(3)

x=160

Final Velocity is equal to 160 m/s

riadik2000 [5.3K]3 years ago

3 0

160 m/s because you start off with 10 and go up by 50*3 which is 150 then add that with the begging speed to achieve 160m/s.

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In the eastern US, hurricanesusually form over the warm waters of the Caribbean Sea and travel north. When they are over the col

garik1379 [7]

Answer:

Less powerful

Explanation:

Hurricanes rely on warm water. It sucks heat energy from the water to use for fuel. Warmer water means more moisture, which also mean a bigger and/or stronger hurricane. The North Atlantic is definitely much colder than the Caribbean so the hurricane will not have much fuel.

Have a great day!

8 0

3 years ago

A small rock is launched straight upward from the surface of a planet with no atmosphere. The initial speed of the rock is twice

Scorpion4ik [409]

If gravitational effects from other objects are negligible, the speed of the rock at a very great distance from the planet will approach a value of $\sqrt{3} v_{e}$

<u>Explanation:</u>

To express velocity which is too far from the planet and escape velocity by using the energy conservation, we get

Rock’s initial velocity , $v_{i}=2 v_{e}$ . Here the radius is R, so find the escape velocity as follows,

$\frac{1}{2} m v_{e}^{2}-\frac{G M m}{R}=0$

$\frac{1}{2} m v_{e}^{2}=\frac{G M m}{R}$

$v_{e}^{2}=\frac{2 G M}{R}$

$v_{e}=\sqrt{\frac{2 G M}{R}}$

Where, M = Planet’s mass and G = constant.

From given conditions,

Surface potential energy can be expressed as, $U_{i}=-\frac{G M m}{R}$

R tend to infinity when far away from the planet, so $v_{f}=0$

Then, kinetic energy at initial would be,

$k_{i}=\frac{1}{2} m v_{i}^{2}=\frac{1}{2} m\left(2 v_{e}\right)^{2}$

Similarly, kinetic energy at final would be,

$k_{f}=\frac{1}{2} m v_{f}^{2}$

Here, $v_{f}=\text { final velocity }$

Now, adding potential and kinetic energies of initial and final and equating as below, find the final velocity as

$U_{i}+k_{i}=k_{f}+v_{f}$

$\frac{1}{2} m\left(2 v_{e}\right)^{2}-\frac{G M m}{R}=\frac{1}{2} m v_{f}^{2}+0$

$\frac{1}{2} m\left(2 v_{e}\right)^{2}-\frac{G M m}{R}=\frac{1}{2} m v_{f}^{2}$

'm' and $\frac{1}{2}$ as common on both sides, so gets cancelled, we get as

$4\left(v_{e}\right)^{2}-\frac{2 G M}{R}=v_{f}^{2}$

We know, $v_{e}=\sqrt{\frac{2 G M}{R}}$ , it can be wriiten as $\left(v_{e}\right)^{2}=\frac{2 G M}{R}$ , we get

$4\left(v_{e}\right)^{2}-\left(v_{e}\right)^{2}=v_{f}^{2}$

$v_{f}^{2}=3\left(v_{e}\right)^{2}$

Taking squares out, we get,

$v_{f}=\sqrt{3} v_{e}$

4 0

3 years ago

6. A baseball player hits a 0.155-kilogram fastball traveling at -44.0 m/s into center field at a speed of 50.0

Zolol [24]

Answer:

3,237.78N

Explanation:

According to Newton's second law of motion

F = mass * acceleration

Since a = v-u/t

F = m(v-u)/t

Given

Mass m = 0.155kg

v = 50.0m/s

u = -44.0m/s

Time t = 0.00450secs

Substitute

F = 0.155(50-(-44))/0.00450

F = 0.155(50+44)/0.00450

F = 0.155(94)/0.00450

F = 14.57/0.00450

F = 3,237.78N

hence he hit the baseball with a force of 3,237.78N

5 0

3 years ago

300kg of water are lifted 10m vertically in 5s show the work done in 30kj and that power is 6kw . Please help me

Mandarinka [93]

Answer:

6KW

Explanation:

The computation is shown below:

We know that

Work done= m ×g× h

Here

W= 300×10×10

= 30000 J

= 30 KJ

And

Power= Work done ÷time taken

P = 30000 ÷ 5

= 6000W

= 6KW

The above represent the answer

3 0

3 years ago

YALL PLS HELP ME! CAN YOU GUYS CHECK MY ANSWERS?

Ugo [173]

Answer:

1. Newton's First Law of Motion

2.Newton's Third Law of Motion

3.Newton's Third Law of Motion

4.Newton's Second Law of Motion

5.Newton's Third Law of Motion

6.Newton's Second Law of Motion

7.Newton's First Law of Motion

Explanation:

Newton's First Law of Motion states that an object remain at rest or moving with a uniform velocity unless an external force acts on it. This is the law of inertia

Newton's Second Law of Motion states that the force of an objects is the product of mass and acceleration.

Newton's Third Law of Motion states that when two objects interact, a pair of forces act on the objects, and they are equal and act in opposite directions.

4 0

3 years ago