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n200080 [17]
3 years ago
13

A beaker contains a mixture of sand and small pebbles. what kind of mixture is this?

Chemistry
1 answer:
melomori [17]3 years ago
3 0
Answer is: a beaker contains <span>heterogeneous mixture.

</span>

A heterogeneous mixture<span> have compounds that remain separate in the sample.</span>

Heterogeneous mixture is not uniform in composition (in this mixture different sand and small pebbles), but proportions of its components (in this mixture particles of different colors and size) vary throughout the sample.

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Which process is characterized by the movement of particles?.
Serjik [45]

Answer: Diffusion is the movement of particles from a high to low particle concentration, while osmosis is the movement of water from a high to a low water concentration.

Explanation:

6 0
3 years ago
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The agent of mechanical weathering in which rock is worn away by the grinding action of other rock particles is call
Igoryamba

Physical weathering

3 0
3 years ago
The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it.
xxTIMURxx [149]

Answer:

Gallium-72

Explanation:

The elements are identified by the number of protons of the atom, which is its atomic number.

In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

Now, to identify the isotope you tell the name of the element and add the mass number.

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Therefore, the isotope is gallium - 72.

3 0
3 years ago
A 25.0g tin sample was placed in boiling water at 99.5 C until it had the same temperature. Afterwards, the tin sample was place
MrMuchimi

Answer : The specific heat of tin is, 0.213 J/g.K

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat lost = -399.4 J

c = specific heat capacity of tin = ?

m = mass of tin = 25.0 g

T_{final} = final temperature = 24.5^oC=273+24.5=297.5K

T_{initial} = initial temperature = 99.5^oC=273+99.5=372.5K

Now put all the given values in the above formula, we get:

-399.4J=25.0g\times c\times (297.5-372.5)K

c=0.213J/g.K

Therefore, the specific heat of tin is, 0.213 J/g.K

7 0
3 years ago
How do I calculate the standard enthalpy change for the following reaction at 25 °C ?
ladessa [460]
MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g) 

Using the standard enthalpies of formation given in the source below: 

(−601.24 kJ) + (2 x −92.30 kJ) − (−641.8 kJ) − (−285.8 kJ) = +141.76 kJ 
So: 

MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g), ΔH = +141.76 kJ
4 0
3 years ago
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