You use an inclined plane to move furniture into a truck. You perform 352 kj of work, but only do 229 kj of useful work. What is
2 answers:
Answer:
The efficiency of the inclined plane is 65.05%.
Explanation:
It is given that, you use an inclined plane to move furniture into a truck.
Work done performed by the person, i.e. input work
Useful work done by the person, i.e. input work
The efficiency of any simple machine is always less than 1. For the inclined plane it is given by :
So, the efficiency of the inclined plane is 65.05%. Hence, this is the required solution.
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Answer:
Total contraction on the Bar = 1.22786 mm
Explanation:
Given that:
Total Length for aluminum bar = 600 mm
Diameter for aluminum bar = 40 mm
Hole diameter = 30 mm
Hole length = 100 mm
elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²
compressive load P = 180 KN = 180 × 10³ N
Calculate the total contraction on the bar = ???
The relation used in calculating the contraction on the bar is:
The relation used in calculating the total contraction on the bar can be expressed as :
Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)
i.e
Total contraction on the Bar =
Let's find the area of cross section without the hole and with the hole
Area of cross section without the hole is :
Using A = πd²/4
A = π (40)²/4
A = 1256.64 mm²
Area of cross section with the hole is :
A = π (40²-30²)/4
A = 549.78 mm²
Total contraction on the Bar =
Total contraction on the Bar =
Total contraction on the Bar = 2.117( 0.398 + 0.182)
Total contraction on the Bar = 2.117*(0.58)
Total contraction on the Bar = 1.22786 mm