Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
Answer:
The speed will be "18km/s". A further explanation is given below.
Explanation:
According to the question, the values are:
Wavelength,
![\lambda = 656.46 \ nm](https://tex.z-dn.net/?f=%5Clambda%20%3D%20656.46%20%5C%20nm)
![\Delta \lambda = 0.04](https://tex.z-dn.net/?f=%5CDelta%20%5Clambda%20%3D%200.04)
![c=3\times 10^8](https://tex.z-dn.net/?f=c%3D3%5Ctimes%2010%5E8)
As we know,
⇒ ![\frac{\Delta \lambda}{\lambda} =\frac{v}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5Clambda%7D%7B%5Clambda%7D%20%3D%5Cfrac%7Bv%7D%7Bc%7D)
On substituting the values, we get
⇒ ![\frac{656.46}{0.04} =\frac{v}{3\times 10^8}](https://tex.z-dn.net/?f=%5Cfrac%7B656.46%7D%7B0.04%7D%20%3D%5Cfrac%7Bv%7D%7B3%5Ctimes%2010%5E8%7D)
⇒ ![v=\frac{656.46}{0.04} (3\times 10^8)](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B656.46%7D%7B0.04%7D%20%283%5Ctimes%2010%5E8%29)
⇒ ![=16411.5\times 3\times 10^8](https://tex.z-dn.net/?f=%3D16411.5%5Ctimes%203%5Ctimes%2010%5E8)
⇒ ![=18280 \ m/s](https://tex.z-dn.net/?f=%3D18280%20%5C%20m%2Fs)
or,
⇒ ![=18 \ km/s](https://tex.z-dn.net/?f=%3D18%20%5C%20km%2Fs)
Hey there!
The answer is :
The <span>humidity you feel in the southern states of the U.S. is water vapor
water vapor is between a gas and liquid so that is what gives a humid feel in the hot sun
Hopes this helps u :D</span>
Answer: ![115.52\ N](https://tex.z-dn.net/?f=115.52%5C%20N)
Explanation:
Given
Length of plank is 1.6 m
Force
is applied on the left side of plank
Force
is applied 43 cm from the left end O.
Mass of the plank is ![m=13.7\ kg](https://tex.z-dn.net/?f=m%3D13.7%5C%20kg)
for equilibrium
Net torque must be zero. Taking torque about left side of the plank
![\Rightarrow mg\times 0.8-F_2\times 0.43=0\\\\\Rightarrow F_2=\dfrac{13.7\times 9.8\times 0.8}{0.43}\\\\\Rightarrow F_2=249.78\ N](https://tex.z-dn.net/?f=%5CRightarrow%20mg%5Ctimes%200.8-F_2%5Ctimes%200.43%3D0%5C%5C%5C%5C%5CRightarrow%20F_2%3D%5Cdfrac%7B13.7%5Ctimes%209.8%5Ctimes%200.8%7D%7B0.43%7D%5C%5C%5C%5C%5CRightarrow%20F_2%3D249.78%5C%20N)
Net vertical force must be zero on the plank
![\Rightarrow F_1+W-F_2=0\\\Rightarrow F_1=F_2-W\\\Rightarrow F_1=249.78-13.7\times 9.8\\\Rightarrow F_1=115.52\ N](https://tex.z-dn.net/?f=%5CRightarrow%20F_1%2BW-F_2%3D0%5C%5C%5CRightarrow%20F_1%3DF_2-W%5C%5C%5CRightarrow%20F_1%3D249.78-13.7%5Ctimes%209.8%5C%5C%5CRightarrow%20F_1%3D115.52%5C%20N)