Answer:
energy is being used to make or break bonds between molecules
Explanation:
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To solve this problem, we should recall that
the change in enthalpy is calculated by subtracting the total enthalpy of the reactants
from the total enthalpy of the products:
ΔH = Total H of products – Total H of reactants
You did not insert the table in this problem, therefore I
will find other sources to find for the enthalpies of each compound.
ΔHf CO2 (g) = -393.5 kJ/mol
ΔHf CO (g) = -110.5 kJ/mol
ΔHf Fe2O3 (s) = -822.1 kJ/mol
ΔHf Fe(s) = 0.0 kJ/mol
Since the given enthalpies are still in kJ/mol, we have to
multiply that with the number of moles in the formula. Therefore solving for ΔH:
ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0
kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>
ΔH = <span>795.2
kJ</span>
Answer:
The answer is flattening
Explanation:
A physical change is generally something that affects the shape of form of the matter and a chemical change results from a chemical reaction. Flames are caused by chemical reactions, as is rust, and the process of a fruit becoming ripe. Thus, the answer is “flattening”.
Answer:
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The type of covalent bond is formed between amino acid molecules during protein synthesis will be <u>"peptide bond".</u>
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A peptide bond would be a sort of covalent link that connects an amino acid's carboxyl group to its amino group. Amino acids itself were comprised of atoms bonded together through covalent bonds.
Two atoms share an electron pair equally in a covalent link. Peptide (amide) but also disulfide links between amino acids, as well as C-C, C-O, and C-N bonds within amino acids, represent examples of significant covalent bonds.
Therefore, the type of covalent bond is formed between amino acid molecules during protein synthesis will be <u>"</u><u>peptide bond"</u><u>.</u>
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To know more about covalent bond
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