Answer:
Explanation:
Given
Let us suppose police car and motorist travel in straight line and police car catches motorist after s distance
Distance travel by motorist
----1
Distance traveled by Police car
----2
from 1 & 2 we get
(a)Velocity of Police car after t sec
(b)time taken by police car is
(c)Distance travel by police car
Dirt that you can not burn typically does no longer have any materials that are flammable at decrease temperatures. Mostly due to the fact it is full of water and non-burnable minerals. But a lot of what's in grime can certainly burn if it is dried. Dirt is made of many unique things.
Let the salmon jump with speed v at an angle of 33.3 degree
So here we can find out the components of his velocity in x and y direction
now the horizontal displacement of the salmon is 3.15 m so he cover this horizontal distance with constant speed as there is no acceleration in x direction
here we can say
now in Y direction it is an accelerated motion as it is accelerated due to gravity
now we will plug in v*t = 3.76
now speed v is given by equation above
so here he must have to jump with minimum speed of 5.25 m/s
Answer:
ΔX = 0.0483 m
Explanation:
Let's analyze the problem, the car oscillates in the direction y and advances with constant speed in the direction x
The car can be described with a spring mass system that is represented by the expression
y = A cos (wt + φ)
The speed can be found by derivatives
= dy / dt
= - A w sin (wt + φ
So that the amplitude is maximum without (wt + fi) = + -1
= A w
X axis
Let's reduce to the SI system
vₓ = 15 km / h (1000 m / 1 km) (1h / 3600s) = 4.17 m / s
As the car speed is constant
vₓ = d / t
t = d / v
ₓ
t = 4 / 4.17
t = 0.96 s
This is the time between running two maximums, which is equivalent to a full period
w = 2π f = 2π / T
w = 2π / 0.96
w = 6.545 rad / s
We have the angular velocity we can find the spring constant
w² = k / m
m = 1200 + 4 80
m = 1520 m
k = w² m
k = 6.545² 1520
k = 65112 N / m
Let's use Newton's second law
F - W = 0
F = W
k x = W
x = mg / k
Case 1 when loaded with people
x₁ = 1520 9.8 / 65112
x₁ = 0.22878 m
Case 2 when empty
x₂ = 1200 9.8 / 65112
x₂ = 0.18061 m
The height variation is
ΔX = x₁ -x₂
ΔX = 0.22878 - 0.18061
ΔX = 0.0483 m