Answer : The mass of silver chlorate will be 2.654 grams.
Explanation :
The balanced chemical reaction is,
![2AgClO_3\rightarrow 2AgCl+3O_2](https://tex.z-dn.net/?f=2AgClO_3%5Crightarrow%202AgCl%2B3O_2)
First we have to calculate the moles of oxygen gas at STP.
As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas
So, 0.466 L volume of oxygen gas present in
mole of oxygen gas
Now we have to calculate the moles of silver chlorate.
From the balanced chemical reaction, we conclude that
As, 3 moles of oxygen produced from 2 moles of silver chlorate
So, 0.0208 moles of oxygen produced from
moles of silver chlorate
Now we have to calculate the mass of silver chlorate.
![\text{Mass of }AgClO_3=\text{Moles of }AgClO_3\times \text{Molar mass of }AgClO_3](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DAgClO_3%3D%5Ctext%7BMoles%20of%20%7DAgClO_3%5Ctimes%20%5Ctext%7BMolar%20mass%20of%20%7DAgClO_3)
Molar mass of silver chlorate = 191.32 g/mole
![\text{Mass of }AgClO_3=0.01387mole\times 191.32g/mole=2.654g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DAgClO_3%3D0.01387mole%5Ctimes%20191.32g%2Fmole%3D2.654g)
Therefore, the mass of silver chlorate will be 2.654 grams.