What’s the answer for this problem?

Why do nuclear power plants use fission rather than fusion to generate

kicyunya [14]

B. Fusion requires very high pressure and temperature.

Explanation:

Nuclear fusion is the combination of atomic nuclei into larger ones with the release of a large amount of energy.

Nuclear fission is the decay process in which a heavy nuclide is bombarded with with neutrons.

Both processes release a huge amount of energy.
But fusion produces far more energy.
The reason why nuclear fusion is not in use is because of the high pressure and temperature needed start it.
The activation energy is high and the energy barrier is very great.
Only the core of the sun naturally favors fusion

learn more:

transmutation brainly.com/question/3433940

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5 0

3 years ago

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Two marbles are launched at t = 0 in the experiment illustrated in the figure below. Marble 1 is launched horizontally with a sp

Alex787 [66]

Answer:

Two marbles are launched at t = 0 in the experiment illustrated in the figure below. Marble 1 is launched horizontally with a speed of 4.20 m/s from a height h = 0.950 m. Marble 2 is launched from ground level with a speed of 5.94 m/s at an angle above the horizontal. (a) Where would the marbles collide in the absence of gravity? Give the x and y coordinates of the collision point. (b) Where do the marbles collide given that gravity produces a downward acceleration of g = 9.81 m/s2? Give the x and y coordinates.

Explanation:

i want the answer i don't know

7 0

3 years ago

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What is the relationship between thermal energy, temperature, pressure?

Ira Lisetskai [31]

Answer: When volume is constant, pressure is directly proportional to temperature. When temperature is constant, pressure is inversely proportional to volume. When pressure is constant, volume is directly proportional to temperature.

Explanation:

6 0

3 years ago

What is the normal force in the image below?

saveliy_v [14]

Answer:

980.7N

Explanation:

F = m * g

F = 100 * 9.807m/ $s^{2}$

F = 980.7N

3 0

3 years ago

In an experiment replicating Millikan’s oil drop experiment, a pair of parallel plates are placed 0.0200 m apart and the top pla

lianna [129]

Answer: See below

Explanation:

<u>Given:</u>

The potential between plates, V = 240 V

Distance between plates, d = 0.02 m

The mass of drop, m = 2x10^-11

Charge on electron, e = 1.6x10^-19

Part (a)

The free-body diagram is attached below

Part (b)

The electric field is given by,

$E=\frac{V}{d}$

On applying force balance, the force on oil drop is equal to the weight of the oil,

$\begin{aligned}F_{E} &=m g \\q E &=m g \\q \frac{V}{d} &=m g \\q &=\frac{m g d}{V}\end{aligned}$

Substituting the given values in the above equation,

$\begin{aligned}&q=\frac{2 \times 10^{-11} \mathrm{~kg} \times 9.8 \mathrm{~m} / \mathrm{s}^{2} \times \frac{1 \mathrm{~N}}{1 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}^{2}} \times 0.02 \mathrm{~m}}{240 \mathrm{~V} \times \frac{1 \mathrm{~N} \cdot \mathrm{m} / \mathrm{C}}{1 \mathrm{~V}}} \\&q=1.63 \times 10^{-14} \mathrm{C}\end{aligned}$

Therefore, the charge on the oil drop is 1.63x10^-14 C

Part (c)

There will be an excess of electrons on the oil drop.

The number of electrons on oil drop can be calculated as,

$\begin{aligned}q &=n e \\1.63 \times 10^{-14} \mathrm{C} &=n \times 1.6 \times 10^{-19} \mathrm{C} \\n &=1.01 \times 10^{5}\end{aligned}$

Therefore, the number of excess electrons is 1.01x10^5

3 0

2 years ago