Answer:
A. Gravitational force
C. Their charges
Explanation:
As we'll discuss in this lesson, he found that the force between charged particles was dependent on only two factors: the distance between the particles and the amount of electric charge that they carried.
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Answer:
5m/s/s
Explanation:
The units for velocity is m/s.
The units for acceleration is m/s/s
So, Determine the change in velocity and divide it by the time that change took place.
(30m/s - 10m/s)/4s = 20m/s/(4s) = 5m/s/s
Electric field strength near the surface of sphere is given by
Now we have
Q = 1 C
R = 5 cm
now electric field is given by
Part B)
Since charge on the sphere is very large to electric field near its surface is too high. So this is reasonable result near it.
Part c)
As per our assumption the charge is uniformly distributed on the surface and there is no effect of surrounding charge or surrounding electric field.
Answer:
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Explanation:
u = Object distance
v = Image distance
f = Focal length = 35
m = Magnification = 2.5
Lens equation
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.