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Mariana [72]
3 years ago
9

What is a newton defined as​

Physics
1 answer:
slava [35]3 years ago
4 0

Answer:

Newton, absolute unit of force in the International System of Units (SI units), abbreviated N. It is defined as that force necessary to provide a mass of one kilogram with an acceleration of one metre per second per second.

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Two identical balls are at rest and side by side at the top of a hill. You let one ball, A, start rolling down the hill. A littl
ICE Princess25 [194]

Answer:

Option b. it has the same position and the same acceleration as A

Explanation:

Let's analyze every statement:

a. it has the same position and the same velocity as A

In the instant where B passes A, they Do have the same position. Velocity however, cannot be the same because if they were, ball B would never pass ball A. So, this is false.

b. it has the same position and the same acceleration as A

As we said in the previous option, the position is the same. The acceleration is gravity for both balls, so this is true.

c. it has the same velocity and the same acceleration as A

Acceleration is the same but velocities are not, so this is false.

d. it has the same displacement and the same velocity as A

The distance they have traveled is the same, so the displacement is the same, but the velocity is not, so this is false.

e. it has the same position, displacement and velocity as A

The position and displacement is the same but not velocity, so this is false.

Only option b is true.

3 0
3 years ago
A 0.22 kg air track glider moving at 0.60 m/s a collides elastically into a 0.44 kg glider at rest. After collision the 0.22 kg
motikmotik
The glider collides elastically  an another glider at rest, in this case we have the coservation of quantity of movement 

m1 v1  + m2 v2 = m1V1 + m2 V2
v is the velocity before the shock, V the velocity after the shock
m1=0.22
v1=0.60m/s
m2=0.44
V1=-0.20m/s
remark that <span>0.44 kg glider is initially at rest, so v2= 0
the equation above can be written  </span><span>m1 v1  = m1V1 + m2 V2 ( because v2=0 at rest)
</span><span>m1 v1  = m1V1 + m2 V2 implies  V2= (m1v1 -m1V1) / m2
</span>
V2=0.22x0.60 -0.22x (-0.20) ] / 0.44= 0.4m/s
4 0
3 years ago
Calculate the displacement of a car waxing point of 11 m to the final positions of 4 meters
Nastasia [14]

Answer:

-7 m

Explanation:

Displacement is a vector connecting the initial position of motion of an object to its final position.

For the car in this problem, we have:

- Initial position: + 11 m

- Final position: + 4 m

Therefore, the vector displacement will be:

d = +4 - (+11) = -7 m

Which means:

- Magnitude of 7 m

- Negative direction

3 0
3 years ago
4. For a series of experimentally measured values give the definition of (a) average or mean value (b) the deviation from the me
Naya [18.7K]

Answer:

a)   x_average = ∑ x_{i} / n , b) Δx_{i} = x_{i} –x_average,

d) σ = √(1/n-1  ∑ Dx_{i}² )

Explanation:

Some definitions are requested

a) the average value is the sum of all the values ​​divided by the number of them, if the uncertainties are random, this is the closest value to the real one

       x_average = ∑ x_{i} / n

b) The deviation from the mean value or absolute error is the measured value minus the average value

       Δx_{i} = x_{i} –x_average

c) is the average value of the deviations

        Δx_average = ∑ Δx_{i} / n

d) It is a measure of the dispersion of the values ​​with respect to their average value, it takes the worst of all cases, widely used for large numbers of data

          σ = √(1/n-1  ∑ Dx_{i}² )

Experimental results should be given as follows

  Average value ± uncertainty and the standard deviation

  (x_average + - Δx_average)

  σ

3 0
3 years ago
60 POINT!!!!!!
Genrish500 [490]
You in college stop cheating
8 0
3 years ago
Read 2 more answers
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