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Vinil7 [7]
3 years ago
6

Assuming that seawater is a 3.50 mass % aqueous solution of NaCl, what is the molality of seawater?

Chemistry
1 answer:
Fantom [35]3 years ago
7 0

Hey there!

Consider 100 g of solution:

Mass of NaCl = 3.50% of mass of seawater

( 3.50 / 100 ) * 100 => 3.50 g

Number of moles as shown below:

Molar mass NaCl = 58.44 g/mol

n = Mass / molar mass

n = 3.50 / 58.44 => 0.059 moles of NaCl

Mass of sweater:

Mass of solution -  Mass of NaCl

100 -  3.50 = 96.5 g

96.5 g in Kg :

96.5 / 1000 => 0.0965 Kg

Therefore ,calculate molality  by using  the  following formula:

molality =  number of moles  of solute / mass of solution

molality = 0.059 / 0.0965

molality = 0.61 m


Hope That helps!

You might be interested in
If 10.57 g of magnesium reacts completely with 6.96 g of oxygen, what is the percent by mass of oxygen in magnesium oxide? Round
Deffense [45]

Answer:

39.7 %

Explanation:

magnesium + oxygen ⟶ magnesium oxide

   10.57 g         6.96 g               17.53 g

According to the <em>Law of Conservation of Mass</em>, the mass of the product must equal the total mass of the reactants.

Mass of MgO = 10.57 + 6.96

Mass of MgO = 17.53 g

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this case,

% O = mass of O/mass of MgO × 100 %

Mass of O = 6.96 g

Mass of MgO = 17.53 g

% O = 6.96/17.53 × 100

% O = 0.3970 × 100

% O = 39.7 %

5 0
3 years ago
How many H atoms in 12H2O?
Ilya [14]

Answer:

24 atoms of H  or 1.4 x 10²⁵ hydrogen atoms

Explanation:

simple method

1 H₂O has  atoms of hydrogen and 1 atom of oxygen

while 12H₂O will have 24 atoms of hydrogen and 12 atom of oxygen

by Avagadros number

molar mass of water H₂0=18.01528 g/mol

1 mole of H₂0 have 2 moles of Hydrogen  

one mole of water= 6.02⋅10²³water molecules =1.2 x 10²⁴hydrogen atoms

12 mole of H₂O   =    1.2 x 10²⁴ x 12=  1.4 x 10²⁵ hydrogen atoms  

<u />

1.4 x 10²⁵ hydrogen atoms   in 12 moles of H₂O

<u />

3 0
3 years ago
Need help ASAP! Describes volume?
frutty [35]

Answer:

a definite to indefinite

Explanation:

because if it is in liquid the volume is trusted,but if it is in gas the volume would have multiplied

i think u can pit it well

8 0
3 years ago
A solution was found to have a 15. 6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path l
sleet_krkn [62]

The correct answer is 0.16138

<u>Solution:</u>

Percentage transmission (%T) of the sample = 15.6

Therefore, Absorbance (A)  2 – log (%T) = 2 – log (15.6) = 0.8069

<u>Use Beer’s law:</u>

A = ε*c*l where ε = molar absorptivity of the solution, c = concentration of the solution, and l = path length of the solution.

Given A = 0.8069 and l = 5.00 cm, we must have

<u>0.8069 = ε*c*(5.00 cm)</u>

ε*c = 0.16138 cm-1

For the next part, assume that ε*c remains constant and we have

A’ = ε*c*l’ where l = 1.00 cm.

Plug in values and write

A’ = (0.16138 cm-1)*(1.00 cm) = 0.16138

The ratio of the light intensity entering the sample to the light intensity exiting the sample at a particular wavelength is defined as the transmittance. Absorption and transmission are two related and different quantities used in spectroscopy. The main difference between absorption and transmission is that absorption measures how much incident light is absorbed as it travels through the material, while transmission measures how much light is transmitted.

Learn more about The absorbance here:-brainly.com/question/14919298

#SPJ4

7 0
1 year ago
7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?
suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

                 n  =  0.8133 mol

4 0
3 years ago
Read 2 more answers
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