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Licemer1 [7]
2 years ago
8

What is the concentration (in M) of a sample of the unknown dye with an absorbance of 0.25 at 542 nm?

Chemistry
1 answer:
Sladkaya [172]2 years ago
5 0

Answer:

see explanation below

Explanation:

Question is incomplete, so in picture 1, you have a sample of this question with the missing data.

Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

A = εlc

Where:

ε: molar absortivity

l: distance of the light in solution

c: concentration of solution

However, in this case, we have a plot line and a equation for this plot, so all we have to do is replace the given data into the equation and solve for x, which is the concentration.

the equation according to the plot is:

A = 15200c - 0.018

So solving for C for an absorbance of 0.25 is:

0.25 = 15200c - 0.018

0.25 + 0.018 = 15200c

0.268 = 15200c

c = 0.268/15200

c = 1.76x10⁻⁵ M

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Calculate the [H3O+] of solutions a and b; calculate the [OH-] solutions c and d.
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Explanation:

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