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shtirl [24]
3 years ago
7

In the reaction AI+3O2->2AI2O3 what coefficient should be placed in front of the AI to balance the reaction 1,2,3,4

Chemistry
1 answer:
patriot [66]3 years ago
8 0

Answer:

To balance the reaction, we should put a 4 in front of Al

Explanation:

<u>Step 1:</u> Data given

AI+3O2->2AI2O3

<u>Step 2:</u> Balance the equation

On the right side we have 2*3 = 6 oxygen atoms

On the left side we have 3*2 = 6 oxygen atoms as well, so those are on both side balanced

On the right side we have 2*2 = 4 Al atoms

On the left side we have only 1 Al atom

We should multiply this by 4 (place a 4 in front of the Al)

4AI + 3O2 → 2AI2O3

Now al atoms are balanced on both sides.

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Explanation:

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The atomic number of sulfur is 16, which indicates that a sulfur atom contains
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4 0
3 years ago
How many Hydrogen atoms are there in 5 g of NH3? (molar mass of NH3 = 17<br>g/mol)​
goldfiish [28.3K]

Answer:5.309 × 10²⁴ atoms.

Explanation:

Given that

molar mass of NH3 = 17 g/mol

Mass of NH3 = 5g

Therefore, No of moles of NH3 = Mass/ molar mass

=  5g/ 17g/mol

= 0.294 moles.

I  mole = 6.02 × 10²³ atoms

Therefore  the number of hydrogen atoms in a 0.294 moles of ammonia  gives us

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5 0
3 years ago
I need help fast thx
Free_Kalibri [48]
I'm guessing you have to balance these.
I took a picture of my working out.

Answer to the first one = 2HCl+CaCO3=CaCl2+H20+CO2
So basically just add a big 2 in front of the first HCl

Answer to second one = 2Ni + O2 = 2NiO
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6 0
4 years ago
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