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Murljashka [212]
3 years ago
6

Give endothermic examples

Chemistry
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

Melting ice cubes.

Melting solid salts.

Evaporating liquid water.

Explanation:

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Name 4 other gases in the atmosphere besides oxygen and nitrogen
Klio2033 [76]
Carbon Dioxide, water vapor, Argon, and I think neon.
6 0
3 years ago
Read 2 more answers
44.90 g of reactants are placed in a beaker
sergiy2304 [10]

Answer:

D. -1882J

Explanation:

We can solve the energy released in a chemical reaction in an aqueous medium using the equation:

Q = -m*C*ΔT

<em>Where Q is energy (In J),</em>

<em>m is mass of water (45.00g)</em>

<em>C is specific heat of water (4.184J/g°C)</em>

<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>

<em />

Replacing:

Q = -45.00*4.184J/g°C*10.00°C

Q = -1882J

Right answer is:

<h3>D. -1882J</h3>

<em />

7 0
3 years ago
650.0 mL of a gas is under a pressure of 840.0 torr. What would the volume of
zheka24 [161]

Answer:

Explanation:using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?

6 0
2 years ago
How much energy must be added to a 1 kg piece of gold with a specific heat of 130 j/kg to increase its temperature from 20 c to
Lorico [155]

Q = 10.4 \; \text{kJ}

The specific heat of a material gives the energy it takes to increase the temperature of one unit mass of the material by one unit temperature. The SI unit for specific heat c is therefore \text{J} /\text{kg} \cdot \textdegree{\text{C}}.

The formula relating the energy required to raise the temperature of m grams of a substance with specific energy c by \Delta T degrees is

Q= c \cdot m \cdot \Delta T

The question provides the following information:

  • c = 130\; \text{J} /\text{kg} \cdot \textdegree{\text{C}} for gold
  • m= 1 \; \text{kg}
  • \Delta T = 100 \textdegree{\text{C}} - 20 \textdegree{\text{C}} = 80 \textdegree{\text{C}}

Apply the formula:

\begin{array}{ccc} Q & = & c \cdot m \cdot \Delta T\\  & = & 130 \; \text{J} \cdot \text{kg}^{-1} \cdot \textdegree{\text{C}}^{-1} \times 1 \; \text{kg} \times 80 \;  \textdegree{\text{C}}\\ & = & 1.04 \times 10^{4} \;\text{J}\\ & = & 10.4 \; \text {kJ} \end{array}

7 0
4 years ago
How many moles are in 17.2g k2s
Natalija [7]

Answer: 0.156 mol

Explanation:

To find the moles of 17.2 g K₂S, we need to know the molar mass to convert.

17.2g*\frac{mol}{110.256 g} =0.156 mol

3 0
4 years ago
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